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Vesna [10]
3 years ago
5

Write the molecular and net ionic equations, including phases, for the reaction that occurs between aqueous sodium chloride, NaC

l , and aqueous silver nitrate, AgNO 3 .
Chemistry
2 answers:
Pavlova-9 [17]3 years ago
6 0

Answer:

Molecular equation: NaCl(aq) + AgNO₃(aq)  →  NaNO₃(aq) + AgCl(s)↓

Net ionic equation:  Cl⁻(aq)  +  Ag⁺(aq)   → AgCl (s)

Explanation:

We determine the reactants for the reaction:

NaCl and AgNO₃

In aqueous solutions, salts from nitrate are soluble (all soluble)

In aqueous solutions, salts from chloride can make precipitate (with Ag⁺, Pb²⁺ Hg²⁺, Cu²⁺)

We dissociate the reactants:

NaCl  →  Na⁺  + Cl⁻

AgNO₃  →  Ag⁺  +  NO₃⁻

Molecular equation: NaCl(aq) + AgNO₃(aq)  →  NaNO₃(aq) + AgCl(s)↓

To build the net ionic equation we pick up the ions:

Na⁺(aq) + Cl⁻(aq)  + Ag⁺(aq)  + NO₃⁻(aq)  → NO₃⁻(aq)  + Na⁺(aq) + AgCl (s)

Those who are solid must be written as a compound, the ions are only from aq solutions. As we find NO₃⁻ and Na⁺ in both sides of the reactions we named them, spectators ions because they do not react. We can cancel them, so the net ionic equation is:  Cl⁻(aq)  +  Ag⁺(aq)   → AgCl (s)

horsena [70]3 years ago
4 0

Answer:

Molecular equation: NaCl(aq) + AgNO3(aq) → AgCl(s) + NaNO3(aq)

net ionic equation: Ag+(aq) + Cl-(aq) → AgCl(s)

Explanation:

Step 1: Data given

aqueous sodium chloride = NaCl(aq)

aqueous silver nitrate = AgNO3(aq)

Step 2: The (un)balanced equation

NaCl(aq) + AgNO3(aq) → AgCl(s) + NaNO3(aq)

This equation is already balanced

Step 3: The net ionic equation

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side, look like this:

Na+(aq) + Cl-(aq) + Ag+(aq) + NO3-(aq) → AgCl(s) + Na+(aq) + NO3-(aq)

Ag+(aq) + Cl-(aq) → AgCl(s)

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Which reactions are oxidation-reduction reactions? check all that apply. fes(s) 2hcl(aq) → h2s(g) fecl2(g) agno3(aq) nacl(aq)
Dafna1 [17]

oxidation-reduction reactions are -

  1. 2C3H6(g) + 9O2(g) → 6CO2(g) + 6H2O(g)
  2. Fe2O3(s) + 3CO(g) → 2Fe(l) + 3CO2(g)

For reaction,

  1. 2C3H6(g) + 9O2(g) → 6CO2(g) + 6H2O(g)

<u>On reactant side</u>:

Oxidation state of Carbon = +2

Oxidation state of Oxygen = 0

<u>On product side:</u>

Oxidation state of Carbon = +4

Oxidation state of Oxygen = -2

Here, carbon's oxidation state is rising from +2 to +4. As a result, it is oxidizing and the oxygen's oxidation state is decreasing from 0 to -2. As a result, it is decreasing.

For reaction,

                Fe2O3(s) + 3CO(g) → 2Fe(l) + 3CO2(g)

<u>When reacting:</u>

Iron's oxidation state is +3.

Carbon's oxidation state is +2.

<u>On product side:</u>

Iron's oxidation state is zero.

Carbon's oxidation state is +4.

Here, carbon's oxidation state is rising from +2 to +4. As a result, it is being oxidized and the iron's oxidation state is changing from +3 to 0. As a result, it is decreasing.

To learn more about oxidation-reduction from given link

brainly.com/question/5794822

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7 0
1 year ago
1 point If the boy is pushing with 50N of force and the static friction resistance is 70N of force, what will happen? *​
solniwko [45]
Nothing, he shouldn’t be able to move it. Think about it like this say you try really hard to push something that is 5,000 pounds and you push as hard as you can. Well you can’t move it bc it weighs more than you can push. I’m sure their is a equation you can use to see how much you can push (body weight=force?)
6 0
3 years ago
With a force of 5 newtons, Amanda pushes the stack of books to the right. At the same time, Jeremy, her little brother, pushes t
Allisa [31]

Answer:

A.  5 N to the left

<em>Note: The question is incomplete. The complete question is given below:</em>

<em>With a force of 5 newtons, Amanda pushes the stack of books to the right. At the same time, Jeremy, her little brother, pushes the stack of books to the left with a force of 10 newtons. </em>

<em>What is the direction and magnitude of the resulting force? </em>

<em>A.  5 N to the left </em>

<em>B.  5 N to the right </em>

<em>C.  10 N to the right </em>

<em>D.  10 N to the left </em>

Explanation:

Forces are vector quantities.

Vector quantities are quantities that can be represented both in magnitude and direction.

Forces have both magnitude and direction. Forces can be directed positively or negatively.

For example, in the question above, if forces acting to the right are considered to be in the positive direction, forces acting to the left are considered to be acting in a negative direction.

In the addition of forces, both their magnitude and direction are taken into consideration.

In the example above, taking forces acting to the right as positive and to the left as negative, the sum of the forces is:

Resultant force, F = (5 N) + (-10N)

F = -5 N

Therefore, the net force is 5 N and is directed towards the left

5 0
3 years ago
Read 2 more answers
A compound is found to have an empirical formula of CH2O. If its molecular mass is 60.0 g/mol, what is its molecular formula?
denpristay [2]
The empirical formula CH₂O has a mass [(12 × 1) + (1 × 2) + (16 × 1)] = 30 g/mol

If the empirical formula is 30 g/mol,
and the molecular formula is 60 g/mol

Then the multiple is = 60 g/mol ÷ 30 g/mol 
                                = 2

Therefor the molecular formula is 2(CH₂O) = C₂H₄O₂   (OPTION 2)
8 0
3 years ago
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Mumz [18]

Answer:

I hope it helps..... you can stop at the full-stop

3 0
2 years ago
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