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IgorLugansk [536]
3 years ago
13

What is the pH of a 0.0042 M hydrochloric acid solution?

Chemistry
1 answer:
babymother [125]3 years ago
4 0

Answer:

E) 2.38

Explanation:

The pH of any solution , helps to determine the acidic strength of the solution ,

i.e. ,

  • Lower the value of pH , higher is its acidic strength

and ,

  • Higher the value of pH , lower is its acidic strength .

pH is given as the negative log of the concentration of H⁺ ions ,

hence ,

pH = - log H⁺

From the question ,

the concentration of the solution is 0.0042 M , and being it a strong acid , dissociates completely to its respective ions ,

Therefore , the concentration of H⁺ = 0.0042 M .

Hence , using the above equation , the value of pH can be calculated as follows -

pH = - log H⁺

pH = - log ( 0.0042 M )

pH =  2.38 .

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Suppose 0.035 moles of HCl is dissolved in enough water to produce 750 mL of solution. What is the pH
zhuklara [117]

Answer:

pH = 1.33

Explanation:

Because HCl is a strong acid, each mole of HCl will completely dissociate into H⁺ and Cl⁻ species.

Now we calculate the molar concentration (molarity) of H⁺:

  • Molarity = moles / volume

(750 mL ⇒ 750 / 1000 = 0.750 L)

  • Molarity = 0.035 moles / 0.750 L
  • Molarity = 0.0467 M

Then we calculate the pH of the solution:

  • pH = -log [H⁺]
  • pH = -log (0.0467 M)
  • pH = 1.33
5 0
2 years ago
PLEASE HELP
otez555 [7]

Answer:

P2≈393.609Kpa so I think the answer is 394 kPa

Explanation:

PV=mRT Ideal Gas Law

m and R are constant because they dont change for the problem. That means

PV/T=mR = constant

so P1*V1/T1=P2*V2/T2 and note that the temperatures are in absolute temperatures (Kelvin) because you can't divide by zero.

So P2 = P1*V1*T2/(V2*T1) = 101325 Pa * 700 mL * 303K/(200 mL*273K)

P2 = 393609 Pa

5 0
3 years ago
Read 2 more answers
PLEASE HELP ME, 20 POINTS
Marrrta [24]

Explanations:

<u>Question</u> <u>1:</u> Lithium in 20.00+ g is C. or D., but 25.00+ g is D. which means this is the correct option.

I am unsure of <u>Question</u> <u>2</u>. I don't think it is mole though.

<u>Question</u> <u>3:</u> Boron in 25.00-30.00 g is B. or D., but 25.00 g would be C.

<u>Question</u> <u>4:</u> 2.393 x 1024 atoms of Oxygen is 63.58 mole O. I don't know for sure, but I think this is correct.

<u><em>I am NOT professional. There is a chance I am incorrect. Please reply to me if I've made a mistake.</em></u>

4 0
2 years ago
If the compound below is oxidized, the resulting product is ___. Select one: a. methane and propane b. butanal c. butanoic acid
Anvisha [2.4K]

The complete question is

If the compound below is oxidized, the resulting product is ___.

the compound given is Butanal

Select one:

a. methane and propane

b. butanal

c. butanoic acid

d. butane

Answer:

C. Butanoic Acid

Explanation:

When Butanal is oxidized using reagents like KMnO4, Tollens reagent etc.

When Aldehyde is oxidized corresponding Carboxylic Acid is produced

 Butanal →  Butanoic Acid

7 0
3 years ago
A liquid occupies a volume of 5.0 L has a mass of 6.0 kg. what is the density of a the lights in kg/L
grandymaker [24]

Answer:

Hey there! :

Volume = 5.0 L

mass = 6.0 Kg

Therefore:

Density = mass / Volume

Density = 6.0 / 5.0

Density = 1.2 kg/L

6 0
3 years ago
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