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Komok [63]
4 years ago
7

A car of mass 1400 kg travelling at 15 m/s goes over a circular arc-shaped bump in the road. if the radius of the arc is 40 m, w

hat is the normal force on the car as it is passing the top of the arc?
Physics
1 answer:
kari74 [83]4 years ago
8 0
The car on the top of the arc;
m = 1,400 kg, v = 15 m/s, r = 40 m;
The normal force:
F n = m g -  m v ² / r =
= 1,400 kg · 9.8 m / s² - (1,400 kg · ( 15 m/s )² : 40 m ) =
= 13,720 N - 7,875 N = 5,845 N
Answer:
B ) 5,800 N 
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Explanation:

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4 years ago
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7. 13 a turbine receives steam at 6 mpa, 600°c with an exit pressure of 600 kpa. Assume the turbine is adiabatic and neglect kin
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The work done by the turbine will be 708.2 kJ/kg. The work done by the turbine is the difference of the enthalpy at inlet and exit.

<h3 /><h3>What is temperature?</h3>

Temperature directs the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles, more the temperature.

If the given turbine is assumed to be reversible;

\rm P_I(Initial pressure)=60 mpa = 60 bar

\rm  T_i(Initial temperature)=600° C

\rm P_e (Exit pressure)=600 kpa=6 bar

The heat balance equation is;

\rm q-W_t=h_e-h_i\\\\ q=0\\\\\ W_t=h_i-h_e

The change in the entropy is;

\rm S_2-S_1=\frac{\delta q}{dt}

The work done by the turbine is;

\rm W_t = h_i-h_e\\\\ W_t =3658.4 -29.5019\\\\  W_t =708.2 \ kJ/kg

Hence,the work done by the turbine will be 708.2 kJ/kg.

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6 0
2 years ago
Visible light falls into wavelength ranges of 400-700 nm, for which 1 m = 1 × 10 9 nm . The energy and wavelength of light are r
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Answer:

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Explanation:

The energy of the photon can be given in terms of its wavelength by the use of the following formula:

E = \frac{hc}{\lambda}

where,

E = energy = ?

h = Plank's Constant = 6.626 x 10⁻³⁴ Js

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λ =  wavelength of light = 560.6 nm = 5.606 x 10⁻⁷ m

Therefore,

E = \frac{(6.626\ x\ 10^{-34}\ Js)(3\ x\ 10^8\ m/s)}{5.606\ x\ 10^{-7}\ m}\\

<u>E = 3.54 x 10⁻¹⁹ J</u>

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Answer:

Answer is It was deduced from the rate at which it glimmers.

Refer below.

Explanation:

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