A car of mass 1400 kg travelling at 15 m/s goes over a circular arc-shaped bump in the road. if the radius of the arc is 40 m, w
1 answer:
You might be interested in
The change in the height of the object is 5.1 m.
<h3>Conservation of mechanical energy</h3>The principle of conservation of mechanical energy states that the total energy of an isolated system is always conserved.
The change in the height of the object is calculated by applying the principle of conservation of mechanical energy as follows;
P.E = K.E
Thus, the change in the height of the object is 5.1 m.
Learn more about conservation of mechanical energy here: brainly.com/question/6852965
Answer:
D) 12.3 m/s downward
Explanation:
We use the next free fall equation
where is the height of the cliff,
the initial velocity,
the acceleration of gravity (
) and
is time.
For the fist rock since the rock was dropped, and
, so we have:
simplifying
the height of the cliff is 44.145m
Now, about the second rock we know that is the same height and now the time es , and we need to find
From the fist equation
we clear for
and substitute known values
wich rounds up to
the direction is downward because the rock is thrown so that it falls through the cliff.