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Vladimir [108]
3 years ago
8

H o m o zygous what does it mean

Physics
1 answer:
lord [1]3 years ago
6 0

Answer:

two identical

Explanation:

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Light could be thought of as a stream of tiny particles discharged by _______ objects that travel in straight paths. *
Gelneren [198K]

Answer: Light could be thought of as a stream of tiny particles discharged by luminous objects that travel in straight paths.

Explanation:

We can define "radiation" as the transmision of energy trough waves or particles.

Particularly, light is a form of electromagnetic radiation, so the "tiny particles" of light are discharged by a radiating object, particularly we can be more explicit and call it a luminous object, in this way we are being specific about the nature of the radiation of the object.

5 0
3 years ago
For numbers 2 and 3, which one is compression and which one is rarefaction?
DENIUS [597]
Compression is above the equilibrium and rarefaction is below
5 0
3 years ago
such smut. when he asks how this goal can be accomplished he volunteers to preview every film that will be shown in town. If Ada
juin [17]
What does this all mean sorry ignore me
6 0
2 years ago
What is the velocity of a 0.8kg ball that has a momentum of 3 kg*m/s?
Marysya12 [62]

The velocity is 3.75

5 0
2 years ago
Notice that all the initial spring potential energy was transformed into gravitational potential energy. If you compressed the s
Nostrana [21]

<u><em>The  question doesn't provide enough data to be solved, but I'm assuming some magnitudes to help you to solve your own problem</em></u>

Answer:

<em>The maximum height is 0.10 meters</em>

Explanation:

<u>Energy Transformation</u>

It's referred to as the change of one energy from one form to another or others. If we compress a spring and then release it with an object being launched on top of it, all the spring (elastic) potential energy is transformed into kinetic and gravitational energies. When the object stops in the air, all the initial energy is now gravitational potential energy.

If a spring of constant K is compressed a distance x, its potential energy is

\displaystyle P_E=\frac{Kx^2}{2}

When the launched object (mass m) reaches its max height h, all that energy is now gravitational, which is computed as

U=mgh

We have then,

U=P_E

\displaystyle mgh=\frac{Kx^2}{2}

Solving for h

\displaystyle h=\frac{Kx^2}{2mg}

We have little data to work on the problem, so we'll assume some values to answer the question and help to solve the problem at hand

Let's say: x=0.2 m (given), K=100 N/m, m=2 kg

Computing the maximum height

\displaystyle h=\frac{(100)0.2^2}{2(2)(9.8)}

\displaystyle h=\frac{4}{39.2}=0,10\ m

The maximum height is 0.10 meters

8 0
3 years ago
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