Question

Calculate change in height of a 2kg ball moving a speed of 10m/s up a frictionless ramp until it stops

Answer 1

The change in the height of the object is 5.1 m.

Conservation of mechanical energy

The principle of conservation of mechanical energy states that the total energy of an isolated system is always conserved.

The change in the height of the object is calculated by applying the principle of conservation of mechanical energy as follows;

P.E = K.E

$mg \Delta h = \frac{1}{2} mv^2\\\\g \Delta h = \frac{1}{2}v^2\\\\\Delta h = \frac{v^2}{2g} \\\\\Delta h = \frac{(10)^2}{2(9.8)} \\\\\Delta h = 5.1 \ m$

Thus, the change in the height of the object is 5.1 m.

Learn more about conservation of mechanical energy here: brainly.com/question/6852965