<span>First law of thermodynamics. This conservation law states that energy cannot be created or destroyed but can be changed from one form to another. In essence, energy is always conserved but can be converted from one form into another. Like when an engine burns fuel, it converts the energy stored in the fuel's chemical bonds into useful mechanical energy and then into heat, or more specifically, the melting ice cubes. Yeast breaks down maltose into glucose to produce alcohol and Co2 in the fermentation process. This is a prime example of the 1st law of thermodynamics. No form of usable energy is really lost; it only changes from one form to another</span>
Answer:
the si unit of electric current is Ampere .the flow of charge in a close circuit is called electric current
C. Both A. and B.
Explanation:
Statement A. Reducing the volume is true because of Boyle's law, which states that for a gas at fixed temperature, the pressure p and the volume V are inversely proportional:
![pV=const.](https://tex.z-dn.net/?f=pV%3Dconst.)
Therefore, when the volume V is reduced, the pressure p increases.
Statement B. Adding more gas is also true: in fact, if we add gas into the container, we will have more molecules of the gas hitting the wall of the container. But the pressure of a gas is exactly given by this: by the collision of the molecules against the wall of the container, so the more the molecules of gas, the greater the pressure.
Answer:
The velocity of the cart at the bottom of the ramp is 1.81m/s, and the acceleration would be 3.30m/s^2.
Explanation:
Assuming the initial velocity to be zero, we can obtain the velocity at the bottom of the ramp using the kinematics equations:
![v=v_0+at\\\\v^2=v_0^2+2ad](https://tex.z-dn.net/?f=v%3Dv_0%2Bat%5C%5C%5C%5Cv%5E2%3Dv_0%5E2%2B2ad)
Dividing the second equation by the first one, we obtain:
![v=\frac{v_0^2+2ad}{v_0+at}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bv_0%5E2%2B2ad%7D%7Bv_0%2Bat%7D)
And, since
, then:
![v=\frac{2ad}{at}\\\\v=\frac{2d}{t}\\\\v=\frac{2(0.50m)}{0.55s}\\\\v=1.81m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B2ad%7D%7Bat%7D%5C%5C%5C%5Cv%3D%5Cfrac%7B2d%7D%7Bt%7D%5C%5C%5C%5Cv%3D%5Cfrac%7B2%280.50m%29%7D%7B0.55s%7D%5C%5C%5C%5Cv%3D1.81m%2Fs)
It means that the velocity at the bottom of the ramp is 1.81m/s.
We could use this data, plus any of the two initial equations, to determine the acceleration:
![v=v_0+at\\\\\implies a=\frac{v}{t}\\\\a=\frac{1.81m/s}{0.55s}\\\\a=3.30m/s^2](https://tex.z-dn.net/?f=v%3Dv_0%2Bat%5C%5C%5C%5C%5Cimplies%20a%3D%5Cfrac%7Bv%7D%7Bt%7D%5C%5C%5C%5Ca%3D%5Cfrac%7B1.81m%2Fs%7D%7B0.55s%7D%5C%5C%5C%5Ca%3D3.30m%2Fs%5E2)
So the acceleration is 3.30m/s^2.