2 years ago

____is the distance traveled during a specific unit of time

Physics

1 answer:

qaws [65]2 years ago

6 0

I think speed is the answer

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What happens to the force between charges when: (a) the distance between them is halved?<br>

charle [14.2K]

Answer:

i dont know but ill update you

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1 year ago

A 1 kg puck sliding on a horizontal shuffleboard court is slowed to rest by 1 point

Citrus2011 [14]

Answer:

miu = 0.31

Explanation:

The friction force is defined as the product of the normal force by the coefficient of friction.

$f=miu*N$

where:

f = friction force = 3 [N]

miu = friction coefficient

N = normal force [N]

The normal force on a horizontal surface can be calculated by means of the product of mass by gravity.

where:

m = mass = 1 [kg]

g = gravity acceleration = 9.81 [m/s²]

$N=m*g\\N=1*9.81$

$N= 9,81 [N]$

Now replacing in the equation above, we can find the friction coefficient.

$miu=3/9.81\\miu = 0.31$

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2 years ago

Who wrote the mayflower compact?

Setler79 [48]

esteban Julio ricardo Montoya de la rosa ramirez

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3 years ago

a cement block accidentally falls from rest from the ledge of a 80.6-m-high building. When the block is 10.8 m above the ground,

fomenos

Answer:

0.229 seconds

Explanation:

Given:

y₀ = 80.6 m

v₀ = 0 m/s

a = -9.8 m/s²

We need to find the difference in times when y = 10.8 m and y = 2.10 m.

When y = 10.8 m:

y = y₀ + v₀ t + ½ at²

10.8 = 80.6 + (0) t + ½ (-9.8) t²

10.8 = 80.6 − 4.9 t²

4.9 t² = 69.8

t = 3.774

When y = 2.10 m:

y = y₀ + v₀ t + ½ at²

2.10 = 80.6 + (0) t + ½ (-9.8) t²

2.10 = 80.6 − 4.9 t²

4.9 t² = 78.5

t = 4.003

The difference is:

4.003 − 3.774 = 0.229

The man has 0.229 seconds to get out of the way.

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3 years ago

For a constant applied force, how does increasing the mass of an object affect it acceleration?

Inessa05 [86]

As the mass of an object increases with a constant force applied to it, its acceleration will ultimately decrease

3 0

2 years ago