Heat is something that really get hot. And transfers is when you send something to another person or another place.
During a climb UP the mountain, gravity does NO work on the climber.
Actually, it's more correct to say that gravity does NEGATIVE work
on him. The climber has to DO the positive work to haul himself up.
Work = (mass) x (gravity) x (height) .
For the guy in this problem:
Work = (67 kg) x (9.8 m/s²) x (3,500 meters)
= 2,298,100 joules.
If he eats no candy bars on the way, and completely depends on
his stored body fat for the energy, then he'll burn off
(2,298,100 joules) / (3.8 x 10⁷ joules/kg)
= 0.06 kg of fat.
That's only about 2.1 ounces. We KNOW he'll lose more weight than that,
climbing 11,000 feet. That's because climbing is pretty inefficient.
In addition to the potential energy you have to give your body weight,
you also have to expend energy breathing, digesting, metabolizing,
and sweating.
Straight linear path
Explanation:
If the universe were completely empty with just one object which is solid moving sphere through the space at a speed of 100km/s, it will move along on a straight path.
An object will continue on a straight path or at rest unless acted upon by an external force. This is the first law of newton.
- Since there is no other mass or body in the universe, it will move along in a straight line.
- Our planet and other bodies moves in parabolic path and elliptical orbits because they are attracted by the gravitational forces of other bodies.
- Any body with mass will attract other bodies and makes it move round it.
- The body with the less mass will orbit in the vicinity of the larger mass.
- But if we have just one body out there, there is no attraction from any other body, it will continue along it's straight path.
learn more:
Gravitational force brainly.com/question/4417434
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Answer:
Explanation:
Let the ball is thrown upwards with speed u and reaches upto height h.
Use III equation of motion
here, final velocity v = 0
So, 
Now as the ball reaches the maximum height, it starts falling freely. Let it strkes with the ground with velocity v'.
here, u = 0
So, 
It means the velocity is same as the velocity of projection.
