how is momentum conserved when a cue ball moving with a velocity of 1.5 m/s strikes another billiard ball white playing pool? Sh
1 answer:
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Answer:
1. 24375 N/C
2. 2925 V
Explanation:
d = 12 cm = 0.12 m
F = 3.9 x 10^-15 N
q = 1.6 x 10^-19 C
1. The relation between the electric field and the charge is given by
F = q E
So,
E = 24375 N/C
2. The potential difference and the electric field is related by the given relation.
V = E x d
where, V be the potential difference, E be the electric field strength and d be the distance between the electrodes.
By substituting the values, we get
V = 24375 x 0.12 = 2925 Volt
Answer:
Explanation:
Given
Ball of mass m
maximum Bearable Tension in string is F
Let length of the cord be L m and moving at a speed of v m/s
Here Tension will Provide Centripetal Force
T=Centripetal Force
Answer:
The magnetic field strength inside the solenoid is .
Explanation:
Given that,
Radius = 2.0 mm
Length = 5.0 cm
Current = 2.0 A
Number of turns = 100
(a). We need to calculate the magnetic field strength inside the solenoid
Using formula of the magnetic field strength
Using Ampere's Law
Where, N = Number of turns
I = current
l = length
Put the value into the formula
(b). We draw the diagram
Hence, The magnetic field strength inside the solenoid is .
