Answer:
Explanation:
First of all, we need to calculate the total energy supplied to the calorimeter.
We know that:
V = 3.6 V is the voltage applied
I = 2.6 A is the current
So, the power delivered is
Then, this power is delivered for a time of
t = 350 s
Therefore, the energy supplied is
Finally, the change in temperature of an object is related to the energy supplied by
where in this problem:
E = 3276 J is the energy supplied
C is the heat capacity of the object
is the change in temperature
Solving for C, we find:
Answer:
10250 N/C leftwards
Explanation:
QA = 4 micro Coulomb
QB = - 5 micro Coulomb
AP = 6 m
BP = 2 m
A is origin, B is at 4 m and P is at 6 m .
The electric field due to charge QA at P is EA rightwards
The electric field due to charge QB at P is EB leftwards
The resultant electric field at P due the charges is given by
E = EB - EA
E = 11250 - 1000 = 10250 N/C leftwards
Answer:
B. Light passes through a small opening
Explanation:
Diffraction is one of the properties of wave defined as the bending of wave around corners. It occurs mostly when waves passes through a tiny opening or slit. The type of waveform generated by the wave depends on the type of opening or slit that the medium passes through. The opening can be tiny or large.
Based on the definition, it can be inferred that the situation that causes light waves to diffract is when the light passes through a small opening. For example, the light of a torch passing through a tiny door hole is diffraction.
Answer:
v = 25 m / s
Explanation:
For this exercise we use the relations and kinematics
first part, the train accelerates from v₀ = 7.0 m/s to 13 m/s in a time t = 8.0 s
v = v₀ + a t
a = 
a = 
a = 0.75 m / s²
second part. Accelerate again for t = 16 s
v = v₁ + a t
for this interval the initial velocity is v₁ = 13 m / s
v = 13 + 0.75 16
v = 25 m / s
Answer:
(D)
Explanation:
A(2,3,4,6,8)
B(6,9,12,15,18)
(AuB)=(2,3,4,6,8,9,12,15,18)
