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Aloiza [94]
3 years ago
13

how is momentum conserved when a cue ball moving with a velocity of 1.5 m/s strikes another billiard ball white playing pool? Sh

ow the work.
Physics
1 answer:
mote1985 [20]3 years ago
8 0

according to conservation of momentum , total sum of momentum of the objects taking part in a collision is same before and after the collision.

Total momentum before collision = Total momentum after the collision

when a cue ball moving at velocity 1.5 m/s hits a billiard ball , transfer of momentum takes place between the balls such that total sum of momentum of cue ball and billiard ball remain same before and after the collision.

hence we say that the momentum is conserved.

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g The electric power needs of a community are to be met by windmills with 40-m-diameter rotors. The windmills are to be located
Ksenya-84 [330]

Answer:

Explanation:

Given Data

The diameter of the wind mills is d = 40m

Velocity of the air is V = 6 m / s

Required power output is:  P ₀ = 2100 k W

Expression to calculate the exergy of the air is

E = V ² / 2

Substitute the value in above expression

E = ( 6 m / s ) ² / 2

E = 18 m ² / s ² x (1kJ/kg / 1000m²/s²)

E = 0.018 k J / k g

Expression to calculate the density of the air is

P v =m R T

m /v = P  /RT ⋯ ⋯( I )

Here  

m  is the mass of the air,  

v  is the volume of the air,  

P  is the atmospheric pressure,  

T  is the standard temperature at the atmospheric pressure and  

R  is the gas constant

As the density is

ρ = m /V

Substitute the value in expression (I)

ρ = 101  kP a /( 0.287 k J / k g ⋅ K ) ( 298 K )

ρ = 1.180 k g / m ²

Expression to calculate the mass flow rate is

m = ρ A V ⋯ ⋯ ( I I )

Here  A  is the area of the windmill

Expression to calculate the  A  is

A = π /4  d ²

Substitute the value in above expression

A = π /4 ( 40 m ²)

A = 1256.63 m ²

Substitute the value in expression (II)

m = ( 1.180 k g / m ³) ( 1256.63 m ²) ( 6 m / s )

m = 8896.94  k g / s

Expression to calculate the maximum power available to the windmill is

P w = m ( V ² /2 )

Substitute the value in above expression

P w = 8896.94  k g / s ( (6m/s)²/2 )

P w = 160144.92 W  × ( 1 W /1000 k W )

P w = 160.144 k W

Expression to calculate the number of windmills required is

n = P o /P w

Substitute the value in above expression

n=2100kw/160.144kw

n=13.11

8 0
3 years ago
What is the mass of an object that experiences a gravitational force of 510 N near Earth's surface?
sineoko [7]

Answer:The mass of an object is 52 kg.

Explanation:

Gravitational force on the object ,F=510 N

Acceleration due to gravity = g = 9.8 m/s^2

Mass of the object = m

Force = mass × acceleration

510 N=m\times 9.8 m/s^2

m=52.04 kg\approx 52 kg

The mass of an object is 52 kg.

8 0
3 years ago
Read 2 more answers
Beginning at the NW corner of the intersection of Pine & 675, thence north 950 feet, thence west 380 feet, thence south 950
Serjik [45]

Answer:

this description is valid for mediadle displacement, bone is an acceptable description

Explanation:

The description of a person's position must be done with a position vector. These vectors must have magnitude, a given direction and a starting point.

In the description this has a starting point corner NO of pine and 675.

Each displacement occurs with respect to the previous one, indicating the magnitude of the displacement and its direction.

After analyzing  this description is valid for mediadle displacement, bone is an acceptable description

6 0
3 years ago
According to Kepler, what do all bodies in orbit around another have in common?
dolphi86 [110]
D.
All follow an elliptical path that has two foci, rather than a circular path.

Kepler found paths are elliptical, not circular
3 0
3 years ago
A child goes down the slide,starting from rest. If the length of the slide is 2m and it takes the child 3 seconds to go down the
lapo4ka [179]

Answer:

0.44 m/s^2

Explanation:

We have the following data:

- distance covered by the child: d = 2 m (length of the slide)

- time taken to cover this distance: t = 3 s

- initial velocity of the child: 0 m/s (he starts from rest)

So we can find the acceleration by using the equation:

d=ut+\frac{1}{2}at^2

Where a is the acceleration.

Substituting the values and solving for a,

a=\frac{2d}{t^2}=\frac{2(2)}{3^2}=0.44 m/s^2

3 0
3 years ago
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