The general formula for the alkyne series is: CnH2n+2 CnH2n CnH2n-2 CnHn+2
1 answer:
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Question is incomplete, complete question is as follows :
Complete Question : .Sulfonation of benzene has the following mechanism:
(1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3
[fast]
(2) SO3 + C6H6 → H(C6H5+)SO3−
[slow]
(3) H(C6H5+)SO3− + HSO4− → C6H5SO3− + H2SO4
[fast]
(4) C6H5SO3− + H3O+ → C6H5SO3H + H2O
[fast]
write the overall rate law for the initial rate of the reaction as a fraction.
Rate=k(________/_________)
Answer:
The overall rate law for the initial reaction is =
Explanation :
Frist of all, all the common terms are cancelled out and written the overall reaction.
As we know that the rate depednant step is the slowest step of the reaction, rate law is :
rate =
But the problem is that SO3 cannot be written in the overall rate law because it is an intermediate.
Rate law for synthesis of S03 is as follows :
rate =
Hence when we substitute equation 2 in equation one,
Rate comes out to be =
Answer:
Explanation:
Hello,
For the given chemical reaction:
We first must identify the limiting reactant by computing the reacting moles of Al2S3:
Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:
Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:
Finally, we compute the percent yield with the obtained 2.10 g:
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