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Sauron [17]
3 years ago
9

What is the length of the hypotenuse of a 45°-45°-90° triangle with leg length 5V3?

Mathematics
1 answer:
timama [110]3 years ago
5 0

Answer:

5\sqrt{6}

Step-by-step explanation:

The easiest way to do this problem is to know that the hypotenuse of a 45-45-90 triangle is equal to \sqrt{2} times the length of a leg.  

So, in your problem the hypotenuse = \sqrt{2}(5\sqrt{3}) = 5\sqrt{6}.   Another way to solve the problem is to use the Pythagorean theorem, but that is a longer way to solve it.

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Answer:

Mathematically speaking, it is 9 - 9

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Let A = {\bullet ,\square, \bigotimes} and B = {\square,\ominus, \bullet}.
lisov135 [29]

(a) With <em>A</em> = {•, □, ⊗} and <em>B</em> = {□, ⊖, •}, we have

<em>A</em> × <em>B</em> = {(•, □), (•, ⊖), (•, •), (□, □), (□, ⊖), (□, •), (⊗, □), (⊗, ⊖), (⊗, •)}

and

<em>B</em> × <em>A</em> = {(□, •), (□, □), (□, ⊗), (⊖, •), (⊖, □), (⊖, ⊗), (•, •), (•, □), (•, ⊗)}

(b) The intersection of the two sets above is

(<em>A</em> × <em>B</em>) ∩ (<em>B</em> × <em>A</em>) = {(•, •), (•, □), (□, •), (□, □)}

Not sure what µ is supposed to represent, but I suppose you meant to again write × as in the Cartesian product. By definition, for any two sets <em>A</em> and <em>B</em>, we have

<em>A</em> × <em>B</em> = {(<em>a</em>, <em>b</em>) | <em>a</em> ∈ <em>A</em> and <em>b</em> ∈ <em>B</em>}

Then

(<em>A</em> × <em>B</em>) ∩ (<em>B</em> × <em>A</em>) = {(<em>a</em>, <em>b</em>) | <em>a</em> ∈ <em>A</em> ∩ <em>B</em> and <em>b</em> ∈ <em>A</em> ∩ <em>B</em>}

In the product found above, notice that • and □ are both elements of <em>A</em> and <em>B</em>, while ⊗ and ⊖ are exclusive to either set.

5 0
3 years ago
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ivanzaharov [21]

Answer:

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Step-by-step explanation:

.3 represents 30 precent, so multiply 540 by .3 to get your awnser this is because the .3 is less than one so the multiplying will not raise the number but lower it to 162

6 0
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55% of 70 round to the nearest tenth
Verizon [17]
70 * 55/100=38.5

Enjoy
3 0
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Answer:

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Hope it helps.

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