Answer = d
using the 30 - 60 - 90 triangle theorem
side across from the angle
across from angle 30 is x
across from angle 60 is x rad. 3
across from 90 is 2x
BC is across from angle 60
so BC is the x rad 3
set the given measurement equal to it
x sqrt 3 = 5
÷ sqrt 3 ÷ sqrt 3
x = (5/ sqrt 3)
multiply top and bottom by the radical to get rid of the radical in the bottom
x = (5/ sqrt 3) × (sqrt 3/sqrt 3)
x = 5 sqrt 3/ 3
since side BC is x
BC = 5 sqrt 3/ 3
* Drawing the triangle diagram would help*
Answer:
https://www.map.mathshell.org/download.php?fileid=1714
Step-by-step explanation:
Go to that website and it should tell you about everything
Use the co‐interior rule, corresponding angle rule, alternate angle rule and vertical opposite angle rule to solve the question above.
angle G5 = angle K1 reason : corresponding angles
angle J1 = angle H3 reason: vertical opposite angles
angle J2 = angle K4 reason: vertical opposite angles
angle G5 = angle K4 reason: co‐ interior angles
angle F6 = angle K4 reason: alternate angle
here's the solution,
=》
![\sqrt{1000 \times 1000}](https://tex.z-dn.net/?f=%20%5Csqrt%7B1000%20%5Ctimes%201000%7D%20)
=》
![10 \times 10 \times 10 \times 10 \times 10 \times 10](https://tex.z-dn.net/?f=10%20%5Ctimes%2010%20%5Ctimes%2010%20%5Ctimes%2010%20%5Ctimes%2010%20%5Ctimes%2010)
=》
![1000](https://tex.z-dn.net/?f=1000)
your answer will be
<h2>1000, </h2>
i hope it helped you......