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3 years ago

15

Dados os vetores a b c representados na figura em que cada quadrícula apresenta lado correspondente a uma unidade de medida é af

irmar que a resultante dos vetores tem módulo

1 answer:

Ganezh [65]3 years ago

8 0

Answer:

La resultante es la suma vectorial de dos o más vectores. Es el resultado de sumar dos o más vectores juntos. Si los vectores de desplazamiento A, B y C se suman, el resultado será el vector R. Como se muestra en el diagrama, el vector R puede determinarse mediante el uso de un diagrama de suma de vectores dibujado a escala y con precisión.

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If a 50microAmps current is flowing then how many electrons pass a point each minute to 2 sig figs? Please add an explanation as

defon

The equation you need to use is $Q=IT$ where Q is the charge in C, I is the current in Amps and T is the time in seconds.

So we have T = 60s
I = $50 \times 10^-^6$ A
let's work out Q
$Q=IT = (50\times 10^{-6}) \times 60 = 3 \times 10^-^3$ C
this is the total charge passing a point in a minute so divide by the charge of one electron ( $1.6 \times 10^{-19}$ ) to find the number of electrons passing the point in a minute which equals $1.875 \times 10^{16}$

6 0

3 years ago

Calculate the ratio of the resistance of 12.0 m of aluminum wire 2.5 mm in diameter, to 30.0 m of copper wire 1.6 mm in diameter

alukav5142 [94]

Answer: 0.258

Explanation:

The resistance $R$ of a wire is calculated by the following formula:

$R=\rho\frac{l}{s}$ (1)

Where:

$\rho$ is the resistivity of the material the wire is made of. For aluminium is $\rho_{Al}=2.65(10)^{-8}m\Omega$ and for copper is $\rho_{Cu}=1.68(10)^{-8}m\Omega$

$l$ is the length of the wire, which in the case of aluminium is $l_{Al}=12m$ , and in the case of copper is $l_{Cu}=30m$

$s$ is the transversal area of the wire. In this case is a circumference for both wires, so we will use the formula of the area of the circumference:

$s=\pi{(\frac{d}{2})}^{2}$ (2) Where $d$ is the diameter of the circumference.

For aluminium wire the diameter is $d_{Al}=2.5mm=0.0025m$ and for copper is $d_{Cu}=1.6mm=0.0016m$

So, in this problem we have two transversal areas:

<u>For aluminium:</u>

$s_{Al}=\pi{(\frac{d_{AL}}{2})}^{2}=\pi{(\frac{0.0025m}{2})}^{2}$

$s_{Al}=0.000004908m^{2}$ (3)

<u>For copper:</u>

$s_{Cu}=\pi{\frac{(d_{Cu}}{2})}^{2}=\pi{(\frac{0.0016m}{2})}^{2}$

$s_{Cu}=0.00000201m^{2}$ (4)

Now we have to calculate the resistance for each wire:

<u>Aluminium wire:</u>

$R_{Al}=2.65(10)^{-8}m\Omega\frac{12m}{0.000004908m^{2}}$ (5)

$R_{Al}=0.0647\Omega$ (6) Resistance of aluminium wire

<u>Copper wire:</u>

$R_{Cu}=1.68(10)^{-8}m\Omega\frac{30m}{0.00000201m^{2}}$ (6)

$R_{Cu}=0.250\Omega$ (7) Resistance of copper wire

At this point we are able to calculate the ratio of the resistance of both wires:

$Ratio=\frac{R_{Al}}{R_{Cu}}$ (8)

$\frac{R_{Al}}{R_{Cu}}=\frac{0.0647\Omega}{0.250\Omega}$ (9)

Finally:

$\frac{R_{Al}}{R_{Cu}}=0.258$ This is the ratio

3 0

3 years ago

How will the plants that grow from a plant fertilized seeds compare to the plants grown from its daughter tubers?

lianna [129]

Answer:

A

Explanation:

the answer would be basicly A

3 0

3 years ago

When a person is jump roping where do they have the most potential<br> energy?

Mazyrski [523]

Answer:

At the bottom when they hit the ground.

7 0

2 years ago

What is the mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25

alexandr1967 [171]

The mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.

HOW TO CALCULATE MASS:

The mass of an object can be calculated by dividing the force applied to the object by its acceleration.

According to this question, a bus can accelerate from rest to 15.5 m/s over 8.25s. The acceleration can be calculated as follows:

a = (v - u)/t

a = 15.5 - 0/8.25

a = 15.5/8.25

a = 1.88m/s²

The mass of the bus = 7500N ÷ 1.88m/s²

The mass of the bus = 3989.4kg

Therefore, the mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.

Learn more about mass at: brainly.com/question/20259048?referrer=searchResults

3 0

3 years ago