<span>p total after can be found using p = mv (since only one ball is in motion we can ignore the second ball) </span> <span>p= 10 * 40 </span> <span>=400 kg* m/s </span>
<span>p total after must also be 400 </span>
<span>p total before = p ball1 + p ball2 </span> <span>m1v1 + m2v2 </span> <span>isolate for the mass of ball 2 </span> <span>m2= (p total - m1v1) / v2 </span> <span>= (400 - 10(20))/ 20 </span> <span>= 200/20 </span> <span>= 10 kg Mark me as brainlest plz