Answer:
0.774g of ethanol
0.970mL of ethanol
Explanation:
Molality is an unit of concentration defined as the ratio between moles of solute and kg of solvent.
In the problem, you need to prepare a 1.2m solution of ethanol (Solute) in t-butanol (solvent).
14.0g of butanol are <em>0.014kg </em>and as you want to prepare the 1.2m solution, you need to add:
0.014kg × (1.2moles / kg) = 0.0168 moles of solute = Moles of ethanol
To convert moles of ethanol to mass you require molar mass (Molar mass ethanol, C₂H₅OH = 46.07g/mol). Thus, mass of 0.0168 moles are:
0.0168moles Ethanol ₓ (46.07g / mol) =
<h3>0.774g of ethanol</h3>
And to convert mass in g to mL you require density of the substance (Density of ethanol = 0.798g/mL):
0.774g ₓ (1mL / 0.798g) =
<h3>0.970mL of ehtanol</h3>
carbon has 4 valence electrons
Answer:
A<em>=</em><em>4</em>
<em>B</em><em>=</em><em> </em><em>4</em><em>+</em><em>2</em><em> </em><em>=</em><em>6</em>
<em>C</em><em>=</em><em>C</em><em>arbon</em>
<em>D</em><em>=</em><em>10</em>
<em>E</em><em>=</em><em>22</em>
<em>F</em><em>=</em><em>Argon</em><em> </em>
