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xeze [42]
1 year ago
6

A dog running to the right at 4 m/s sees a ball and accelerates steadily to catch it. The dog accelerates to the right at a rate

of 0.21 m/s^2 and catches the ball after 3.8s. What was the dogs velocity when it caught the ball? *Assume here that running to the right is positive and running to the left is negative.
A- 7.96
B- 10.569
C- 6.782
D- 4.798
E- none
Physics
1 answer:
antoniya [11.8K]1 year ago
6 0

Answer:

D.-4.798m/s

Explanation:

Greetings !

Given values

u= 4ms \\ a = 0.21ms {}^{2}  \\ t = 3.8sec

Solve for V of the given expression

Firstly, recall the velocity-time equation

v = u + at

plug in known values to the equation

v = (4) + (0.21)(3.8)

solve for final velocity

v = 4.792ms

Hope it helps!

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