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xeze [42]
1 year ago
6

A dog running to the right at 4 m/s sees a ball and accelerates steadily to catch it. The dog accelerates to the right at a rate

of 0.21 m/s^2 and catches the ball after 3.8s. What was the dogs velocity when it caught the ball? *Assume here that running to the right is positive and running to the left is negative.
A- 7.96
B- 10.569
C- 6.782
D- 4.798
E- none
Physics
1 answer:
antoniya [11.8K]1 year ago
6 0

Answer:

D.-4.798m/s

Explanation:

Greetings !

Given values

u= 4ms \\ a = 0.21ms {}^{2}  \\ t = 3.8sec

Solve for V of the given expression

Firstly, recall the velocity-time equation

v = u + at

plug in known values to the equation

v = (4) + (0.21)(3.8)

solve for final velocity

v = 4.792ms

Hope it helps!

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How can the sun have both a brightness of -26.73 and 4.83? Explain what these numbers mean.
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3 0
3 years ago
An 1120 kg car traveling at 17.2 m/s is brought to a stop while skidding 40m. Calculate the work done on the car by the friction
Nesterboy [21]

Answer:

Work = 165670.4 J = 165.67 KJ

Explanation:

First, we will find the deceleration of the car, using the 3rd equation of motion:

2as = v_{f}^2 - v_{i}^2\\

where,

a = deceleration = ?

s = skid distance = 40 m

vf = final speed = 0 m/s

vi = initial speed = 17.2 m/s

Therefore,

2a(40\ m) = (0\ m/s)^2 - (17.2\ m/s)^2\\a = - 3.698\ m/s^2

the negative sign indicates deceleration here.

Now, we will calculate the braking force applied by the brakes on the car:

F = ma\\F = (1120\ kg)(-3.698\ m/s^2)\\F = - 4141.76\ N

the negative sign indicates braking force.

Now, we will calculate the work done using the magnitude of this force:

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<u>Work = 165670.4 J = 165.67 KJ</u>

8 0
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