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andrew11 [14]
3 years ago
14

A car travels in a straight line for 4.4 h at a constant speed of 81 km/h. What is its acceleration?

Physics
2 answers:
Fed [463]3 years ago
7 0

The speed and length of time don't matter.

Constant speed in a straight line is the DEFINITION of ZERO acceleration.

irga5000 [103]3 years ago
5 0

Answer:

a = 0m/s^2

Explanation:

we can use the equation:

v_f = a(t) + v_i

And plug in our numbers:

81km/h = am/s^2(4.4h) + 81hm/h

0 = am/s^2(4.4h)

0 = am/s^2

a = 0m/s^2

Because the speed was constant, there was no difference between the final and initial velocities, meaning that once you do the math you see there is no acceleration affecting the speed.

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I also noted the "initial" and "final" height of the swing with hi and hf respectively.

So initially looking at this i thought, what the heck, there's no mass. Then i figured that using the conservation of energy law i could take the mass value from the Ek equation and use it in the Ep equation. So what i did was take the Ek equation and rearranged it for m as you can hopefully see. Then i substituted the rearranged Ek equation into the Ep equation.

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Then i simplify the equation a little. When i multiply both sides by v^2 i can clearly see that there is one E on each side (at that stage i don't need to clarify which type of energy it is because Ek = Ep so they're just the same anyway). So i just canceled them out and square rooted both sides.

The answer i got was that the max velocity would be 4.85m/s 3sf, assuming no losses (eg energy lost to friction).

I do hope I'm right and i suppose it's better than a blank piece of paper good luck my dude xx

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