All categories

3 years ago

A car travels in a straight line for 4.4 h at a constant speed of 81 km/h. What is its acceleration?

Physics

2 answers:

Fed [463]3 years ago

7 0

The speed and length of time don't matter.

Constant speed in a straight line is the DEFINITION of ZERO acceleration.

irga5000 [103]3 years ago

5 0

Answer:

$a = 0m/s^2$

Explanation:

we can use the equation:

$v_f = a(t) + v_i$

And plug in our numbers:

$81km/h = am/s^2(4.4h) + 81hm/h$

$0 = am/s^2(4.4h)$

$0 = am/s^2$

$a = 0m/s^2$

Because the speed was constant, there was no difference between the final and initial velocities, meaning that once you do the math you see there is no acceleration affecting the speed.

You might be interested in

Shalnov [3]

Answer:

No.

Explanation:

Given the following :

Velocity (V) of ball = 5m/s

Radius = 1m

Can the ball reach the highest point of the circular track

of radius 1.0 m?

The highest point in the track could be considered as the diameter of the circle :

Radius = diameter / 2;

Diameter = (2 * Radius) = (2*1) = 2

Maximum height which the ball can reach :

Using the relation :

Kinetic Energy = Potential Energy

0.5mv^2 = mgh

0.5v^2 = gh

0.5(5^2) = 9.8h

0.5 * 25 = 9.8h

12.5 = 9.8h

h = 12.5 / 9.8

h = 1.2755

h = 1.26m

Therefore maximum height which can be reached is 1.26m.

Since h < Diameter

7 0

4 years ago

May I get some help please?

ziro4ka [17]

Arrows point away from both north and south.

7 0

3 years ago

A ticker-tape is moved through a ticker-timer for 5 seconds . if the timer is operating at 25 Hz. i.How many dots would have bee

svetlana [45]

Answer:

Explanation:

25 cycles/s (5 s) = 125 dots

Tape does Repetitious motion.

It might possibly be harmonic motion, but we do not have enough information to say for certain.

8 0

3 years ago

An electron has a constant acceleration of +3.3 m/s2. at a certain instant its velocity is +8.6 m/s. what is its velocity (a) 2.

Citrus2011 [14]

Hello!

The velocity function is:

$\mathsf{V = V_0 + at}\\ \\ \mathsf{V = 8.6 +3.3t}$

a) 2.3 s earlier, we can make t = -2.3 s, in relation to our initial time:

$\mathsf{V = 8.6 + 3.3\cdot(-2.3)}\\ \\ \mathsf{V = 8.8-7.59}\\ \\ \boxed{\mathsf{V = 1.21 \ m/s}}$

b) Now we can make t = 2.3 s:

$\mathsf{V = 8.6 + 3.3\cdot2.3}\\ \\ \mathsf{V = 8.6 + 7.59}\\ \\ \boxed{\mathsf{V = 15.59 \ m/s}}$

7 0

4 years ago

The light reactions could be viewed as analogous to a hydro-electric dam. In that case, the wall of the dam that holds back the

Viktor [21]

The light reactions could be viewed as analogous to a hydroelectric dam. In that case, the wall of the dam that holds back the water would be analogous to the thylakoid membrane.

Thylakoid membrane is present in cyanobacteria and chloroplasts of plants. It plays a crucial role in photosynthesis and photosystem II reactions.

In general, these are the regions where light-dependent reactions take place. The thylakoid membrane is a lipid-bound membrane that maintains potential difference and also controls the flow of liquids across the membrane during light reactions.

In the provided case, we can see that the wall of the dam holds back the water, similarly, in light-dependent reactions, thylakoid membranes control the liquid flow and also regulate the potential gradient across the membrane and also allow the selective proteins to pass through.

If you need to learn more about light reactions click here:

brainly.com/question/26623807

#SPJ4

3 0

2 years ago