The axis of symmetry always passes through the vertex of the parabola . The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola. For a quadratic function in standard form, y=ax2+bx+c , the axis of symmetry is a vertical line x=−b2a .
The answer would be 2(6x+5+2y) you can figure this out through the distributive property. 2(6x)=12x 2(5)=10 and 2(2y)= 4y this would reult in giving you the equation 12x+10+4y
