Answer:
Explanation:
Let the magnetic field be B = B₁i + B₂j + B₃k
Force = I ( L x B ) , I is current , L is length and B is magnetic field .
In the first case
force = - 2.3 j N
L = 2.5 i
puting the values in the equation above
- 2.3 j = 8 [ 2.5 i x ( B₁i + B₂j + B₃k )]
= - 20 B₃ j + 20 B₂ k
comparing LHS and RHS ,
20B₃ = 2.3
B₃ = .115
B₂ = 0
In the second case
L = 2.5 j
Force = I ( L x B )
2.3i−5.6k = 8 ( 2.5 j x (B₁i + B₂j + B₃k )
= - 20 B₁ k + 20B₃ i
2.3i−5.6k = - 20 B₁ k + 20B₃ i
B₃ = .115
B₁ = .28
So magnetic field B = .28 i + .115 B₃
Part A
x component of B = .28 T
Part B
y component of B = 0
Part C
z component of B = .115 T .
For the answer to the question above asking to c<span>alculate the work done to stretch an elastic string by 40cm if a force of 10N produces an extension of 4cm in it. The needed force for this is 100N of work</span>
Answer:
The correct option is: begins the hydrolysis of proteins in the stomach
Explanation:
Pepsin is a protease enzyme that is <u>synthesized by the stomach</u>. It is the main gastric enzyme that helps in the <u>digestion of proteins molecules </u>present in the food.
The pepsin enzyme catalyzes the<u> acid hydrolysis of the peptide bond in the proteins</u> at a very<u> low acidic pH of 1.5-2.0.</u>
This enzyme becomes <u>inactive at pH 6.0</u> and gets <u>fully denatured or irreversibly inactivated as the pH increases to 8.0</u>.
Answer:
Answer: The dark patch formed due to obstruction of light rays by an opaque object is called a shadow. ... A shadow is formed when an opaque object is placed in the path of light.
i am not sure of that
thank you
Explanation:
let the mass of the two objects be m₁ and m₂ respectively and the distance between the two objects be "r₁" initially.
the gravitational force between the two objects initially is then given as
F₁ = G m₁ m₂ /r₁² eq-1
where G = universal gravitational constant
when the objects are moved closer and the distance between the objects become one third of the original distance, hence
r₂ = distance after objects moved closer = r₁/3
new gravitational force between the objects after they are moved closed is given as
F₂ = G m₁ m₂ /r₂² eq-2
dividing eq-2 by eq-1
F₂/F₁ = (G m₁ m₂ /r₂² )/(G m₁ m₂ /r₁²)
F₂/F₁ = r₁²/r₂²
we know that , r₂ = r₁/3
hence
F₂/F₁ = r₁²/(r₁/3)²
F₂/F₁ = 9
F₂ = 9 F₁
hence the gravitational force becomes nine times its initial value