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mixas84 [53]
3 years ago
5

On the other side of the gorge, at the highest point of his swing, the vine makes an angle of \theta=40^\circθ=40 ​∘ ​​ from the

vertical. At this point, Tarzan's speed is instantaneously zero (as he transitions from swinging up to swinging back again). What is the tension in the vine at the highest point of his swing?
Physics
1 answer:
SVEN [57.7K]3 years ago
7 0

Answer:

T = m*g*cos\theta

Explanation:

Since tarzan moves in a circular trajectory we can sum all forces on the centripetal-axis:

T - m*g*cos\theta = m*a_c

T - m*g*cos\theta = m*V^2/R   Since the speed is zero:

T - m*g*cos\theta = 0

T = m*g*cos\theta Having Tarzan's mass we could calculate the module of the tension in the vine.

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Answer:

3.258 m/s

Explanation:

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x = Displacement of spring = 0.7 m (Assumed, as it is not given)

\mu = Coefficient of friction = 0.4

Energy stored in spring is given by

U=\dfrac{1}{2}kx^2\\\Rightarrow U=\dfrac{1}{2}\times 263\times 0.7^2\\\Rightarrow U=64.435\ J

As the energy in the system is conserved we have

\dfrac{1}{2}mv^2=U-\mu mgx\\\Rightarrow v=\sqrt{2\dfrac{U-\mu mgx}{m}}\\\Rightarrow v=\sqrt{2\dfrac{64.435-0.4\times 8\times 9.81\times 0.7}{8}}\\\Rightarrow v=3.258\ m/s

The speed of the 8 kg block just before collision is 3.258 m/s

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3 years ago
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Answer:

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Explanation:

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7 0
3 years ago
Find equation tangent to a circle at given point
vlabodo [156]

the equation of the tangent line must be passed on a point A (a,b) and perpendicular to the radius of the circle. <span>
I will take an example for a clear explanation:
let x² + y² = 4 is the equation of the circle, its center is C(0,0). And we assume that the tangent line passes to the point A(2.3).

</span>since the tangent passes to the A(2,3), the line must be perpendicular to the radius of the circle. 

<span>Let's find the equation of the line parallel to the radius.</span>

<span>The line passes to the A(2,3) and C (0,0). y= ax+b is the standard form of the equation. AC(-2, -3) is a vector parallel to CM(x, y).</span>

det(AC, CM)= -2y +3x =0, is the equation of the line // to the radius.

let's find the equation of the line perpendicular to this previous line.

let M a point which lies on the line. so MA.AC=0 (scalar product), 

it is (2-x, 3-y) . (-2, -3)= -4+4x + -9+3y=4x +3y -13=0 is the equation of tangent



7 0
3 years ago
Question 15 plz picture above
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15) C. The amount of each element that begins....
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3 years ago
A sample of aluminum has a mass of 4.86 grams and a volume of 1.8 cubic centimeters. What is the density of aluminum rounded to
TEA [102]

Answer:

3g/cm³

Explanation:

2.7

The seven adds 1 to the 2 making it 3.0

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