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grin007 [14]
3 years ago
5

Enc is working as an insurance salesperson. He earns a base salary and a commission on each new policy

Mathematics
2 answers:
klio [65]3 years ago
8 0

Answer: Ok, what is the question Asking after $1,220?

Step-by-step explanation:

mihalych1998 [28]3 years ago
7 0

Answer:

Oh well Is that it explain more

Step-by-step explanation:

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Please help asap or give explanation for brainliest
Mama L [17]

Answer:

Hi, I believe 1-0.25c is the correct answer.

Step-by-step explanation:

This is because 25% off would mean taking 25 off of a whole amount, which in this case would be one.

6 0
2 years ago
Read 2 more answers
An arithmetic sequence has the following properties:
WINSTONCH [101]

Answer:

Easy peasy

Step-by-step explanation:

7+(n-1)5

3 0
3 years ago
Markers are on sale for $4.50 for Black, $3.25 for Red, and $1.98 for Green. He spends a total of $284.24. If he buys a certain
mixas84 [53]
Let x be number of black markers

4.5x + 2x3.25x + 3x1.98x = 284.24
16.94x = 284.24
x = 16.78 = 17

The person bought 17 black pens, 34 red and 51 green
5 0
3 years ago
Please answer this in two minutes
solniwko [45]

Answer:

30

Step-by-step explanation:

a^2 + b^2 = c^2

(8sqrt(3))^2 + b^2 = 16^2

64 * 3 + b^2 = 256

192 + b^2 = 256

b^2 = 64

b = 8

The ratio of the lengths of the sides of this triangle is

8 : 8sqrt(3) : 16

which reduces to

1 : sqrt(3) : 2

This is the ratio of the lengths of the sides of a 30-60-90 triangle.

m<W = 30 deg

5 0
2 years ago
Let g(x)=Intragal from 0 to x f(t) dt, where r is the function whos graph is shown.
leonid [27]

If

\displaystyle g(x) = \int_0^x f(t) \, dt

then g(x) gives the signed area under f(x) over a given interval starting at 0.

In particular,

\displaystyle g(0) = \int_0^0 f(t) \, dt = 0

since the integral of any function over a single point is zero;

\displaystyle g(4) = \int_0^4 f(t) \, dt = 8

since the area under f(x) over the interval [0, 4] is a right triangle with length and height 4, hence area 1/2 • 4 • 4 = 8;

\displaystyle g(8) = \int_0^8 f(t) \, dt = 0

since the area over [4, 8] is the same as the area over [0, 4], but on the opposite side of the t-axis;

\displaystyle g(12) = \int_0^{12} f(t) \, dt = -8

since the area over [8, 12] is the same as over [4, 8], but doesn't get canceled;

\displaystyle g(16) = \int_0^{16} f(t) \, dt = 0

since the area over [12, 16] is the same as over [0, 4], and all together these four triangle areas cancel to zero;

\displaystyle g(20) = \int_0^{20} f(t) \, dt = 24

since the area over [16, 20] is a trapezoid with "bases" 4 and 8, and "height" 4, hence area (4 + 8)/2 • 4 = 24;

\displaystyle g(24) = \int_0^{24} f(t) \, dt = 64

since the area over [20, 24] is yet another trapezoid, but with bases 8 and 12, and height 4, hence area (8 + 12)/2 • 4 = 40, which we add to the previous area.

5 0
2 years ago
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