Rachel is putting 3,902 bagels into a box if she puts 8 bagels in each box how many boxes can she fill in total.

HELP ME ASAP HELP ME ASAP HELP ME ASAP

Anon25 [30]

Answer:

First, plot the y-intercept. The y-intercept is 1, so plot the point (0,1).

Then go up 2 points and to the right 3 points and plot a point there. (3,3)

We go to the right because the slope is positive.

Draw a line through the two points.

Step-by-step explanation:

y = mx+b

m = slope

b = y-intercept

8 0

3 years ago

Help me pls math genius

Alecsey [184]

Answer:

x = -3

y = -1

Step-by-step explanation:

in the given question :-

=》x - 4y = 1

=》x = 4y + 1

now replacing the value of x as ( 4y + 1 ) in equation (2)

=》3x + 2y = -11

=》3 (4y + 1) + 2y = -11

=》12y + 3 + 2y = -11

=》14y = -11 - 3

=》y = -14 ÷ 14

=》y = -1

now, putting the value of y in equation (1)

=》x - 4y = 1

=》x - ( 4 × -1 ) = 1

=》x + 4 = 1

=》x = 1 - 4

=》x = -3

6 0

3 years ago

Read 2 more answers

What is the midpoint of the line segment with endpoints(-2,-2) and (4,6)

Ann [662]

Answer:

The midpoint of points $(-2,-2)\ and\ (4,6)$ is $(1,2)$ .

Step-by-step explanation:

Given points are $(-2,-2)\ and\ (4,6)$ . We need to find the midpoint of the line segment.

The formula of finding midpoints between the point $(x_1,y_1)\ and\ (x_2,y_2)$ is

$(\frac{x_1+x_2}{2}),(\frac{y_1+y_2}{2})\ Equation(1)$

W have points $(x_1,y_1)=(-2,-2)$ . And $(x_2,y_2)=(4,6)$

Let us plug the value in Equation (1)

$(\frac{-2+4}{2} ),(\frac{-2+6}{2})$

$(\frac{2}{2}),(\frac{4}{2})\\ \\(1,2)$

So, the midpoint of points $(-2,-2)\ and\ (4,6)$ is $(1,2)$ .

3 0

3 years ago

Estimate the area of Alberta in square miles. Show your reasoning

ella [17]

Answer: About $278,250\ mi^2$

Step-by-step explanation:

The missing figure is attached.

Notice in the first picture that Alberta has a complex shape.

You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.

Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.

The area of the trapezoid can be calcualted with the formula:

$A_t=\frac{h}{2}(B+b)$

Where "h" is the height, "B" is the long base and "b" is short base.

And the area of the rectangle can be found with the formula:

$A_r=lw$

Wkere "l" is the lenght and "w" is the width.

Then, the apprximate area of Alberta is:

$A=\frac{h}{2}(B+b)+lw$

Substituting vallues, you get:

$A=(\frac{(410\ mi-180\ mi)}{2})(760\ mi+470\ mi)+(180\ mi)(760\ im)\\\\A=141,450\ mi^2+136,800\ mi^2\\\\A=278,250\ mi^2$

Therefore, the area of of Alberta is about $278,250\ mi^2$ .

5 0

3 years ago

Help me please it is literal equation

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

s = n(a + 1)

n(a + 1) = s

a + 1 = s/n

a = s/n - 1

8 0

3 years ago