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Amiraneli [1.4K]
4 years ago
14

Assuming all volume measurements are made at the same temperature and pressure, how many liters of oxygen gas would it take to r

eact completely with 7.25 liters of hydrogen gas? Show all of the steps taken to solve this problem. (4 points) Balanced equation: 2H2 (g) + O2 (g) yields 2H2 O(g)
Chemistry
1 answer:
EleoNora [17]4 years ago
3 0
2H2 (g) + O2 (g) -->2H2 O(g)
mole ratio of H2:O2=2:1
7.25/2=3.625
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I think is true not sure but it might be
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4 years ago
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PLEASE HELP WHAT IS THE CORRECT ANSWER (if possible let me know why)
ANTONII [103]

Answer:I’m not 100% sure but I think it’s the first answer.

Explanation:

The pressure would increase as the molecules are pushing out word more and more, leading to more space being taken and more pressure. But then again, I’m not sure. I’m just a freshman with below average grades.

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3 years ago
In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas to produce ga
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Answer:

0.41kg/sec

Explanation:

PV= nRT

Given : V= 505 L

P=0.88 atm

R= 0.08206 Latm/K*mol

T= 172 .0C = 172+273 = 445 K

n = PV /RT = 0.88 * 505 / 0.08206 * 445 = 12.17 moles per sec of N2 are consumed

As per reaction : N2 + 3H2 ----> 2NH3

1 mole N2 is consumed to produce 2 moles NH3

moles of NH3 produced per sec :

(2 moles NH3/1mol N2) * 12.17 moles N2 = 24.34 moles NH3 per sec

grams of NH3 produced per sec =

24.34 moles NH3 per sec * molar mass NH3 = 24.34 moles NH3 per sec * 17.031 g/mol = 414.5 g NH3 per sec

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5 0
3 years ago
What is an orderly, three dimensional arrangement formed by ions called?
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4 years ago
The reaction 2HgO (s)→2Hg (I)+O2 (g) has a percent yield of 50%. You want to produce 100 g of Hg.
nevsk [136]

The mass of HgO needed for the reaction is 216 g

The correct answer to the question is Option C. 216 g

We'll begin by calculating the theoretical yield of Hg.

  • Actual yield of Hg = 100 g
  • Percentage yield = 50%
  • Theoretical yield of Hg =?

Theoretical yield = Actual yield / percentage yield

Theoretical yield = 100 / 50%

Theoretical yield of Hg = 200 g

Finally, we shall determine the mass of HgO needed for the reaction.

2HgO → 2Hg + O₂

Molar mass of HgO = 201 + 16 = 217 g/mol

Mass of HgO from the balanced equation = 2 × 217 = 434 g

Molar mass of Hg = 201 g/mol

Mass of Hg from the balanced equation = 2 × 201 = 402 g

From the balanced equation above,

402 g of Hg were produced from 434 g of HgO.

Therefore

200 g of Hg will be produce by = (200 × 434) / 402 = 216 g of HgO.

Thus, 216 g of HgO is needed for the reaction.

Learn more about stoichiometry:

brainly.com/question/24426334

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