Answer: 5.1 gram
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of require = 1 mole of
Thus 0.41 moles of will require= of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
Moles of HCl left = (0.55-0.41) = 0.14
Mass of left =
Thus 5.1 g of hydrochloric acid could be left over by the chemical reaction.
Answer:
3.75 g.
Explanation:
<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>
<em />
<em>mass % = (mass of solute/mass of solution) x 100.</em>
<em></em>
mass of calcium nitrite = ??? g,
mass of the solution = 25.0 g.
∴ mass % = (mass of solute/mass of solution) x 100
<em></em>
<em>∴ mass of solute (calcium nitrite) = (mass %)(mass of solution)/100</em> = (15.0 %)(25.0 g)/100 = <em>3.75 g.</em>
Answer:
The number of oxygen in 7.9 × 10⁻¹ moles of CO₂ is 9.5116 × 10²³ atoms of oxygen
Explanation:
The given parameters are;
The number of moles of CO₂ = 7.9 × 10⁻¹ moles
The number of molecules of CO₂ in one mole of CO₂ = 6.02 × 10²³
The number of molecules, , of CO₂ in 7.9 × 10⁻¹ moles is given as follows;
= 7.9 × 10⁻¹ × 6.02 × 10²³ ≈ 4.76 × 10²³ molecules
The number of atoms of oxygen in one molecule of CO₂ = 2 oxygen atoms
Therefore;
The number of oxygen in 7.9 × 10⁻¹ moles of CO₂ = 2 × 4.76 × 10²³ ≈ 9.5116 × 10²³
The number of oxygen in 7.9 × 10⁻¹ moles of CO₂ ≈ 9.5116 × 10²³ atoms of oxygen.
Answer:
Kinetic energy
Explanation:
Fireworks convert chemical energy into kinetic energy to send them flying upward. Hope it is correct!