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Leona [35]
3 years ago
14

Only radioactive isotopes are useful for radiometric dating or medical diagnostic exams. Briefly explain why stable isotopes wou

ld not be useful in either of these applications.
Chemistry
1 answer:
Mnenie [13.5K]3 years ago
8 0

Answer:

Explanation:

Isotopes are atoms of elements that have the same atomic number but different mass number hence ISOTOPY. Radioactive Isotopes on the other hand are unstable as they either undergo Alpha decay, beta decay or gamma decay compared to stable isotopes.

Radioactive elements decay at varyinf rates as such the rate of radioactive decay is used in the characterization of radioactive element and mostly expressed in terms of the half life of the radioactive elements.

Half life is the time taken for half of the total atoms of an elements to decay into half of its initial sizes. for example, the half life of radium-226 is 1622 years, it implies that if we have 1000000 radium atoms at the beginning, then at the end of 1622years, 500000 would have disintegrated. These phenomenon can never be experienced by stable isotopes as such they can not be used in carbon dating techniques. reason why uranium-238 is mostly and commonly used in the earth crust to estimate the ages of rocks because it has a half life of 4.5 x 10^9 years.

And also, the radioactive isotopes of most common light element are short, they have very short half life (few days or weeks) and they decay rapidly to vanshing point, as such, they are not found in nature to any reasonable extent.

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500 mL of water is added to 400 mL of 0.35 M HCl. Find the concentration of the diluted solution.
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The concentration of diluted solution is 0.16 M

<u>Explanation:</u>

As, the number of moles of diluted solution and concentrated solution will be same.

So, the equation used to calculate concentration will be:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated HCl solution

M_2\text{ and }V_2 are the molarity and volume of diluted HCl solution

We are given:

M_1=0.35M\\V_1=400mL\\M_2=?M\\V_2=(500+400)mL=900mL

Putting values in above equation, we get:

0.35\times 400=M_2\times 900\\\\M_2=\frac{0.35\times 400}{900}=0.16M

Hence, the concentration of diluted solution is 0.16 M

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