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4vir4ik [10]
2 years ago
9

Two types of liquids, two types of gases, two types of solids.

Chemistry
2 answers:
JulsSmile [24]2 years ago
5 0
Liquid=soda, water
Gases=air, carbon dioxide
Solid=food, ice
snow_tiger [21]2 years ago
3 0

Answer:

liquids: water and soda

gases: oxygen and carbon dioxide

solid: a chair and a notebook

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4HCl(g)+O2(g)⟶2Cl2(g)+2H2O(g) Calculate the number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2. mass:
FromTheMoon [43]

The number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2 is 13.6675 g.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given data:

Moles of hydrochloric acid = 0.385 mol

Mass of chlorine gas =?

Chemical equation:

4HCl +  O₂ → 2Cl₂  + 2H₂O

Now we will compare the moles of Cl₂ with HCl.

                 HCl           :               Cl₂

                   4             :               2

                0.385       :              2÷4× 0.385 = 0.1925 mol

Oxygen is present in excess that's why the mass of chlorine produced depends upon the available amount of HCl.

Mass of Cl₂ :

Mass of Cl₂ = moles × molar mass

Mass of Cl₂ =0.1925 mol × 71 g/mol

Mass of Cl₂ =  13.6675 g

Hence, the number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2 is 13.6675 g.

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

6 0
2 years ago
0.5 kg or 0.5 lb which is a larger quantity
masha68 [24]
The correct answer is 0.5 kg If you whant me to explaine pls tell me
3 0
3 years ago
How do liquids with high velocity differ from liquids with low velocity
Yanka [14]

Answer:

whah the other dude said :) also stay safe

Explanation:

5 0
3 years ago
Question 6 of 10
love history [14]
B. Newton’s second law
6 0
2 years ago
What is the pH of a 0.28 M solution of ascorbic acid
Nady [450]

Hey there!

Values Ka1 and Ka2 :

Ka1 => 8.0*10⁻⁵

Ka2 => 1.6*10⁻¹²

H2A + H2O -------> H3O⁺  + HA⁻

 Ka2 is very less so I am not considering that dissociation.

Now Ka = 8.0*10⁻⁵ = [H3O⁺] [HA⁻] / [H2A]

lets concentration of H3O⁺  = X then above equation will be

8.0*10−5 = [x] [x] / [0.28 -x

8.0*10−5 = x² /  [0.28 -x ]

x² + 8.0*10⁻⁵x  - 2.24 * 10⁻⁵

solve the quardratic equation

X =0.004693 M

pH = -log[H⁺]

pH = - log [ 0.004693 ]

pH = 2.3285

Hope that helps!

3 0
3 years ago
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