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Harrizon [31]
3 years ago
14

Outer and inner planets are different in ----- and ------ (also known as what they are made from) a. size and compasion b. lumin

osity and glittery-ness c. color and shape d. friendliness and charisma
Chemistry
1 answer:
Finger [1]3 years ago
3 0

Answer:

a. size and composition

Explanation:

The inner planets differs from the outer planets mostly and mainly in terms of their sizes and composition.

Inner planets are also know as the terrestrial planets. They are the first four planets closest to the sun. They are mostly solids with rocky masses.

The outer planets are located beyond the asteroid belts. They are the last four planets before the Kuiper belt objects. These planets are also called Jovian planets predominantly made up of gases.

The inner planets are smaller compare to the outer planets in size.

The outer planets are gas giants and the inner planets are rocky masses.

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What happens to the temperatures when we have direct sunlight vs indirect sunlight?
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Explanation:

When we have direct sunlight, the temperature is higher compared to indirect sunlight.

Direct sunlight is usually overhead whereas indirect sunlight is at an angle to the surface.

  • Direct sunlight impacts the surface with more energy concentrated on a smaller surface area.
  • This warms the surface more.
  • Indirect sunlight is diffuse and spreads over a wider area.
  • This leads to a reduction in temperature.
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What is a hot spot?<br> Own words
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Which of the following occurs when an electron moves from a higher energy shell to a lower energy shell?
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7 0
3 years ago
When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea
Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

5 0
3 years ago
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