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vredina [299]
3 years ago
12

When dissolved in water, acids produce ____.

Chemistry
1 answer:
vodka [1.7K]3 years ago
6 0

answer:Arrhenius theory: According to this theory, acid produces hydrogen or hydronium ions in a solution, while the base produces hydroxide ions in a solution

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What element is represented by the following electron configuration:
Alecsey [184]
For better representation, let me rewrite the electronic configuration:

<span>1s</span>²<span>2s</span>²<span>2p</span>⁶<span>3s</span>²<span>3p</span>⁶<span>4s</span>²<span>3d</span>⁴

The exponents represent the number of electrons in the designated subshell. Thus, the total number of electrons are:
# of electrons = 2+2+6+2+6+2+4 = 24

Assuming this is in neutral state, the element with an atomic number of 24 is Chromium. Thus, the answer is Cr.
6 0
3 years ago
Can a substance be a lewis acid without being a bronsted-lowry acid?argue
storchak [24]

Answer:

Yes

Explanation:

Yes, A substance can be a lewis acid without being a Bronsted-Lowery acid because there are some substances which cannot donate protons(Bronsted-Lowery acid) but can accept a pair of electron.

<u><em>For Example:</em></u>

Let us take the example of BF₃

BF₃ contains no proton so it is not a Bronsted Lowery Acid

However, BF₃ has an incomplete octet with 6 electrons. It needs an electron pair to complete its octet. It accepts a pair of electron to become a Lewis Acid

6 0
3 years ago
Read 2 more answers
Use the exponential term in the Arrhenius equation to explain how temperature affects reaction rate.
WINSTONCH [101]

The Arrhenius equation describes the relation between the rate of reaction and temperature for many physical and chemical reactions

It is an expression that provides a relationship between the rate constant (of a chemical reaction), the absolute temperature.

The Arrhenius equation,

k = zpe^{\frac{- Ea}{RT} }, where

k is the rate constant,

z is the collision factor,

p is the steric factor,

Ea is the activation energy,

R = 8.3245 \frac{J}{mol. K} is the ideal gas constant, and,

T is the temperature.

The activation energy by definition, is the minimum energy (or threshold energy) required for two particles of reactants upon collision to form products.

The Arrhenius equation could also be written as:

⇒ k = Ae\frac{-Ea}{RT}, where

⇒ A = zp, the Arrhenius factor.

Taking the neutral logarithm of both parties, we get:

⇒ In k = \frac{-Ea}{RT}\frac{(1)}{(T)} + In A,

Assuming that, A is independent of temperature, when T is increased, the equilibrium constant k will also increase and therefore, the rate of the reaction will also increase.

To learn more about Arrhenius equation here

brainly.com/question/9786461

#SPJ4

6 0
2 years ago
The rate constant for a first order reaction
Lena [83]

Answer:

E_a = 103.626 × 10³ KJ/mol

Explanation:

Formula to solve this is given by;

Log(k2/k1) = (E_a/2.303R)((1/T1) - (1/T2))

Where;

k2 is rate constant at second temperature

k1 is rate constant at first temperature

R is universal gas constant

T1 is first temperature

T2 is second temperature

We are given;

k1 = 2.8 × 10^(-3) /s

k2 = 4.8 × 10^(-4) /s

R = 8.314 J/mol.k

T1 = 60°C = 333.15 K

T2 = 45°C = 318.15 K

Thus;

Log((4.8 × 10^(-4))/(2.8 × 10^(-3))) = (E_a/(2.303 × 8.314))((1/333.15) - (1/318.15))

We now have;

-0.76592 = -0.00000739121E_a

E_a = -0.76592/-0.00000739121

E_a = 103.626 × 10³ KJ/mol

8 0
3 years ago
4.0 L of He(g), 6.0 L of N2(g), and 10. L of Ar(g), all at 0°C and 1.0 atm, are pumped into an evacuated 8.0 L rigid container,
lesantik [10]

Answer:

The final pressure in the container at 0°C is 2.49 atm

Explanation:

We apply the Ideal Gases law to know the global pressure.

We need to know, the moles of each:

P He . V He = moles of He . R . 273K

(1atm . 4L) / R . 273K = moles of He  → 0.178 moles

P N₂ . V N₂ = moles of N₂ . R . 273K

(1atm . 6L) / R . 273K = moles of N₂ → 0.268 moles

P Ar . V Ar = moles of Ar . R . 273K

(1atm . 10L) / R . 273K = moles of Ar → 0.446 moles

Total moles: 0.892 moles

P . 8L = 0.892 mol . R . 273K

P = ( 0.892 . R . 273K) / 8L = 2.49 atm

R = 0.082 L.atm/mol.K

3 0
3 years ago
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