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3 years ago

In which situation is no work considered to be done by a force?

Chemistry

2 answers:

Masja [62]3 years ago

7 0

If the angle is either 0 or 180, that means that there is either negative or positive work, so A and D are not correct.

If the angle is 45, then there is still some work involved.

The only option where there is no work done by a force is B. when the angle is between the force and displacement is 90.

san4es73 [151]3 years ago

6 0

Answer:

The correct answer is option B.

Explanation:

Work done is defined as product of applied force to an object and displacement that is distance covered by an object when force applied.

$W=Force\times distance\times \cos\theta$

When $\theta =0^o or 180^o$ . positive or negative work will be done.
When $\theta =45^o$ s, some amount wok will be done
When $\theta =90^o$ no work will be done.

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At anode 2 $Cl^{-}$ ==> Cl₂+ $2e^{-}$ + H₂O ==> $ClO^{-}$ + 2 $H^{+}$ + $Cl^{-}$

At Cathode: 2 $H^{+}$ + $2e^{-}$ ==> H₂

Since the question states that you are using an aqueous solution of MnCl₂, so ions will have present are, H₂O, $H^{+}$ , $Mn^{2+}$ and $Cl^{-}$

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2 $Cl^{-}$ ==> Cl₂+ $2e^{-}$ + H₂O ==> $ClO^{-}$ + 2 $H^{+}$ + $Cl^{-}$ (will occur)

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2 $H^{+}$ + $2e^{-}$ ==> H₂ (will occur)

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The deposition of solid Mn will not occur because in aqueous solution, $H^{+}$ will be reduced before $Mn^{2+}$ .

The reduction potentials for $H^{+}$ is zero whereas reduction potential for $Mn^{2+}$ is - 1.18V.

The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.

To learn more about the half reaction please click on the link brainly.com/question/13186640

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