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Scilla [17]
3 years ago
7

4.0 L of He(g), 6.0 L of N2(g), and 10. L of Ar(g), all at 0°C and 1.0 atm, are pumped into an evacuated 8.0 L rigid container,

the final pressure in the container at 0°C is
Chemistry
1 answer:
lesantik [10]3 years ago
3 0

Answer:

The final pressure in the container at 0°C is 2.49 atm

Explanation:

We apply the Ideal Gases law to know the global pressure.

We need to know, the moles of each:

P He . V He = moles of He . R . 273K

(1atm . 4L) / R . 273K = moles of He  → 0.178 moles

P N₂ . V N₂ = moles of N₂ . R . 273K

(1atm . 6L) / R . 273K = moles of N₂ → 0.268 moles

P Ar . V Ar = moles of Ar . R . 273K

(1atm . 10L) / R . 273K = moles of Ar → 0.446 moles

Total moles: 0.892 moles

P . 8L = 0.892 mol . R . 273K

P = ( 0.892 . R . 273K) / 8L = 2.49 atm

R = 0.082 L.atm/mol.K

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lbvjy [14]

Answer: hello your question lacks some data attached below is the missing data

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Explanation:

we will select the longest carbon chain as the branched alkane and name it

a) 3-methyl heptane ( first diagram )

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8 0
3 years ago
A solution of H2SO4 with a molal concentration of 5.25m has a density of 1.266 g/ml. what is the molar concentration of this sol
Gelneren [198K]
So first find the moles of the H₂SO₄: Mass = Moles x RFM 
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6 0
3 years ago
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Answer:

D

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4 0
2 years ago
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OverLord2011 [107]

 The value  that describe  temperature and  pressure (STP)    is 273.15  K  and  101.3  KPa  (answer D)


 <em><u>Explanation</u></em>

International  union of pure  and applied chemistry (  IUPAC)  established  standard  temperature and pressure (STP)  as below,

temperature  0°c    which   is the same as   273.15 K  

Pressure =  1 atm   which  is the same  = 101.325 KPa   or  1.01325 bar

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