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Tom [10]
4 years ago
10

The decomposition of 11.0 g of fe2o3 results in

Chemistry
1 answer:
Nezavi [6.7K]4 years ago
7 0
2Fe2O3=4Fe+3O2
1 mole Fe2O3=56*2+3*16=160g
2*160g Fe2O3.....4*56gFe.....6*16g O
11gFe2O3....x g Fe....y g O
x=11*4*56/(2*160)=7.7 g Fe
y=11*6*16/(2*160)=3.3g O
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Which statement about fusion reactors is true? a Enriched uranium isotopes are used as fuel in fusion reactors. b Fuel for fusio
trapecia [35]

Answer:

b Fuel for fusion reactors can be extracted from ocean water.  

Explanation:

The fuel is deuterium, which makes up 0.02% of the hydrogen atoms in water. The oceans contain more than a billion cubic kilometres of water, so that's a lot of deuterium.

a is wrong. The fuel for fusion reactors is deuterium.

c is wrong.  There is much research, but there are no large-scale fusion reactors in operation.

d is wrong. Fusion reactors do not produce radioactive waste as spent fuel. Most of the radioactive waste would be the reactor core itself.

6 0
3 years ago
Picture a neutral P atom. This neutral atom will have
aleksandr82 [10.1K]

Answer:

It will have 5 valence electrons as its in group 5.

The atom will gain as its closer to the full configuration 8.

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3 0
3 years ago
Find the mass of 250.00 ml of benzene. The density of benzene is 0.8765 g/ml. (Please show how you got this answer)
Ivenika [448]

Density is Mass per Volume

so

0,8765 g/ml = Mass of Benzene / 250 ml

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so 250 ml of benzene is equal to 219,125 gram

4 0
3 years ago
The electrons between atoms in metallic bonds
fgiga [73]

Answer:

Metallic bonding is the type of chemical bonding that occurs between atoms of metals. In a metallic bond, atoms share their electrons in a way that allows them to form a “sea” of free electrons. This electron sea is responsible for the unique physical and electrical properties of metals.

Explanation:

8 0
2 years ago
given the following equation: 8 H2 + S8 −−> 8H2S what is the molar relationship between H2 and H2S
PSYCHO15rus [73]
-(1/8)Δ[H2S]/Δt = -(1/4)Δ[O2]/Δt
(1/8)Δ[H2S]/Δt = (1/4)Δ[O2]/Δt
(4)*((1/8)Δ[H2S]/Δt) = (4*)((1/4)Δ[O2]/Δt)
(1/2)Δ[H2S]/Δt = Δ[O2]/Δt
(1/2))*( -0.057 M/s) = Δ[O2]/Δt
Δ[O2]/Δt = -0.0285 M/s
4 0
3 years ago
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