Answer:
all of the above
Explanation:
they all require speed to beat
7. PE=0.5×700n/m×0.9m^2
0.9^2=0.81m
0.5×700×0.81= 283.5J
8. 2000=0.5×(x)×1.5m^2
1.5^2= 0.25
0.25×0.5=0.125
2000=0.125 (x)
2000/0.125=x
x=16000 n/m
9. 4000=0.5 (375 n/m)×(x)^2
0.5×187.5 (x)
4000/187.5=21.3333333333
Answer:
17.63W
Explanation:
The total energy supplied to the ice is used to melt the ice. Since the ice starts to melt at and also melts completely at the same temperature, the latent heat of fusion will be the focus in solving this problem.
Latent heat of fusion is defined as the amount of energy that changes a solid substance to liquid state without any change in temperature. It is given by the following relationship;
where m is the mass of the substance and l is the specific latent heat of fusion of the substance.
The specific latent heat of fusion of ice is approximately.
The total heat supplied to the ice was used to melt the ice and is calculated using equation (1), given that m = 4.56kg.
The total energy supplied to the ice is equivalent to the average power P entering the ice multiplied by the time t for which the power is supplied. Therefore;
where t = 1 day and 1 day = 24 hours.
24 hours = 60 x 60 x 24s =86400s.
Hence, t = 86400s.
Substituting into equation (2), we get the following;
Answer: 12.67 cm, 8 cm
Explanation:
Given
Normal distance of separation of eyes, d(n) = 6 cm
Distance of separation is your eyes, d(y) = 9.5 cm
Angle created during the jump, θ = 0.75°
To solve this, we use the formula,
θ = d/r, where
θ = angle created during the jump
d = separation between the eyes
r = distance from the object
θ = d/r
0.75 = 9.5 / r
r = 9.5 / 0.75
r = 12.67 cm
θ = d/r
0.75 = 6 / r
r = 6 / 0.75
r = 8 cm
Thus, the object is 12.67 cm far away in your own "unique" eyes, and just 8 cm further away to the normal person eye