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Anna11 [10]
3 years ago
7

Our eyes are typically 6 cm apart. Suppose you are somewhat unique, and yours are 9.50 cm apart. You see an object jump from sid

e to side by 0.75 degree as you blink back and forth between your eyes. How far away is the object
Physics
1 answer:
Serhud [2]3 years ago
8 0

Answer: 12.67 cm, 8 cm

Explanation:

Given

Normal distance of separation of eyes, d(n) = 6 cm

Distance of separation is your eyes, d(y) = 9.5 cm

Angle created during the jump, θ = 0.75°

To solve this, we use the formula,

θ = d/r, where

θ = angle created during the jump

d = separation between the eyes

r = distance from the object

θ = d/r

0.75 = 9.5 / r

r = 9.5 / 0.75

r = 12.67 cm

θ = d/r

0.75 = 6 / r

r = 6 / 0.75

r = 8 cm

Thus, the object is 12.67 cm far away in your own "unique" eyes, and just 8 cm further away to the normal person eye

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cricket20 [7]

Answer:

-6N

Explanation:

The force to the east is acting in the positive x-direction therefore it is positive. The force to the east is in the negative x-direction therefore it is negative. The net force is just the sum of the two so 3-9=-6

4 0
2 years ago
What is the difference between collinear and coplanar
DIA [1.3K]

Answer:

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Calculate the height of a cliff if it takes 2.35 s for a rock to hit the ground when it is thrown straight up from the cliff wit
pantera1 [17]

Answer:

height of a cliff is 45.86 m

Explanation:

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7 0
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Pls answer need help
igomit [66]

Answer:

See below

Explanation:

Find the NET forces on the objects

A  20==>

B    0

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 next is A because it has the next biggest force

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6 0
2 years ago
Based on the graph, how would you describe the net forces acting on the moving
ladessa [460]

Given the velocity-time graph of an object.

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From the graph, we can see that the slope of the graph is zero. That is, the velocity of the object is constant and hence the net acceleration acting on the object is zero.

From Newton's second law, the net force acting on an object is given by the product of the mass of the object and its velocity. Therefore when the acceleration of the object is zero, the net force on the object is also zero.

Therefore the net force acting on the given object is zero. Hence, the correct answer is option A.

3 0
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