Given
v = 343 m/s
ac = 5g
ac = 5*9.8 m/s^2
ac = 49 m/s^2
where,
v: velocity
ac = centripetal aceleration
Procedure
We call the acceleration of an object moving in uniform circular motion—resulting from a net external force—the centripetal acceleration ac; centripetal means “toward the center” or “center seeking”.
Formula
The minimum radius not to exceed the centripetal acceleration is 2401 m.
Answer:
The escape velocity on the planet is approximately 178.976 km/s
Explanation:
The escape velocity for Earth is therefore given as follows
The formula for escape velocity, , for the planet is
Where;
= The escape velocity on the planet
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
m = The mass of the planet = 12 × The mass of Earth,
r = The radius of the planet = 3 × The radius of Earth,
The escape velocity for Earth, , is therefore given as follows;
= 16 ×
Given that the escape velocity for Earth, ≈ 11,186 m/s, we have;
The escape velocity on the planet = ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.