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Anna11 [10]
3 years ago
7

Our eyes are typically 6 cm apart. Suppose you are somewhat unique, and yours are 9.50 cm apart. You see an object jump from sid

e to side by 0.75 degree as you blink back and forth between your eyes. How far away is the object
Physics
1 answer:
Serhud [2]3 years ago
8 0

Answer: 12.67 cm, 8 cm

Explanation:

Given

Normal distance of separation of eyes, d(n) = 6 cm

Distance of separation is your eyes, d(y) = 9.5 cm

Angle created during the jump, θ = 0.75°

To solve this, we use the formula,

θ = d/r, where

θ = angle created during the jump

d = separation between the eyes

r = distance from the object

θ = d/r

0.75 = 9.5 / r

r = 9.5 / 0.75

r = 12.67 cm

θ = d/r

0.75 = 6 / r

r = 6 / 0.75

r = 8 cm

Thus, the object is 12.67 cm far away in your own "unique" eyes, and just 8 cm further away to the normal person eye

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Explanation:

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3 years ago
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inn [45]

(a) 4.74 \cdot 10^{14}Hz

The frequency of a wave is given by:

f=\frac{v}{\lambda}

where

v is the wave's speed

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v=c=3\cdot 10^8 m/s (speed of light)

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(b) 427.6 nm

The wavelength of the wave in the glass is given by

\lambda=\frac{\lambda_0}{n}

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5 0
4 years ago
A crane lifts an air conditioner to the top of a building. If the building is 12 m high, and the air conditioner has a mass of 2
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Work needed = 23,520 J

<h3> Further explanation </h3>

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Work is the product of force with the displacement of objects.  

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F = Force, N  

d = distance, m  

F = m x g

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Answer:

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