Initially, the velocity vector is
. At the same height, the x-value of the vector will be the same, and the y-value will be opposite (assuming no air resistance). Assuming perfect reflection off the ground, the velocity vector is the same. After 0.2 seconds at 9.8 seconds, the y-value has decreased by
, so the velocity is
.
Converting back to direction and magnitude, we get ![\langle r,\theta \rangle=\langle \sqrt{29.11^2+24.23^2},tan^{-1}(\frac{29.11}{24.23}) \rangle = \langle 37.87,50.2^{\circ}\rangle](https://tex.z-dn.net/?f=%5Clangle%20r%2C%5Ctheta%20%5Crangle%3D%5Clangle%20%5Csqrt%7B29.11%5E2%2B24.23%5E2%7D%2Ctan%5E%7B-1%7D%28%5Cfrac%7B29.11%7D%7B24.23%7D%29%20%5Crangle%20%3D%20%5Clangle%2037.87%2C50.2%5E%7B%5Ccirc%7D%5Crangle)
Answer:
9 times
Explanation:
Kinetic energy is:
KE = ½ mv²
When we triple the velocity, the kinetic energy increases by a factor of 9.
9KE = ½ m(3v)²
Electroreception is limited to aquatic environments because on here is the resistivity of the medium is low enough for electric currents to be generated as the result of electric fields of biological origin. In air, the resistivity of the environment is so high that electric fields from biological sources do not generate a significant electric current. Electroreceptor are found in a number of species of fish, and in at least one species of mammal, the Duck-Billed platypus.
Answer:D
Explanation:
Given
mass of object ![m=5 kg](https://tex.z-dn.net/?f=m%3D5%20kg)
Distance traveled ![h=10 m](https://tex.z-dn.net/?f=h%3D10%20m)
velocity acquired ![v=12 m/s](https://tex.z-dn.net/?f=v%3D12%20m%2Fs)
conserving Energy at the moment when object start falling and when it gains 12 m/s velocity
Initial Energy![=mgh=5\times 9.8\times 10=490 J](https://tex.z-dn.net/?f=%3Dmgh%3D5%5Ctimes%209.8%5Ctimes%2010%3D490%20J)
Final Energy![=\frac{1}{2}mv^2+W_{f}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2%2BW_%7Bf%7D)
![=\frac{1}{2}\cdot 5\cdot 12^2+W_{f}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5Ccdot%205%5Ccdot%2012%5E2%2BW_%7Bf%7D)
where
is friction work if any
![490=360+W_{f}](https://tex.z-dn.net/?f=490%3D360%2BW_%7Bf%7D)
![W_{f}=130 J](https://tex.z-dn.net/?f=W_%7Bf%7D%3D130%20J)
Since Friction is Present therefore it is a case of Open system and net external Force is zero
An open system is a system where exchange of energy and mass is allowed and Friction is acting on the object shows that system is Open .