It’s going to be both answer A and B but if you can only answer one then it’s going to be B
        
             
        
        
        
Answer:
spring compressed is 0.724 m 
Explanation:
given data 
mass = 1.80 kg
spring constant k = 2 × 10²  N/m
initial height = 2.25 m
solution
we know from conservation of energy is 
mg(h+x)  = 0.5 × k × x²       ...................1
here x is compression in spring 
so put here value in equation 1 we get 
1.8 × 9.8 × (2.25+x)  = 0.5 × 2× 10² × x² 
solve it we get 
x = 0.724344
so spring compressed is 0.724 m 
 
        
             
        
        
        
consider east-west direction along X-axis  and north-south direction along Y-axis
 = velocity of migrating robin relative to air = 12 j m/s
 = velocity of migrating robin relative to air = 12 j m/s 
(where "j" is unit vector in Y-direction)
 = velocity of air relative to ground = 6.3 i m/s
 = velocity of air relative to ground = 6.3 i m/s 
(where "i" is unit vector in X-direction)
 = velocity of migrating robin relative to ground = ?
 = velocity of migrating robin relative to ground = ?
using the equation 
 =
 =  +
 + 
 = 12 j + 6.3 i
 = 12 j + 6.3 i
 = 6.3 i + 12 j
 = 6.3 i + 12 j
magnitude : sqrt((6.3)² + (12)²) = 13.6 m/s 
direction : tan⁻¹(12/6.3) = 62.3 deg north of east
 
        
             
        
        
        
Did you try looking it up ?