the highest directly measured frequency is 5.20 x 10^14 Hz, corresponding to one of the transitions in iodine-127. How many wave
1 answer:
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a) The angular velocity of the electron is
b) The number of revolutions per second is rev/s
c) The centripetal acceleration of the electron is
Explanation:
a)
This is a problem of uniform circular motion: in fact, the electron orbits around the proton in a uniform circular motion.
The angular velocity of an object in uniform circular motion is given by
where
v is the linear speed
r is the radius of the trajectory
For the electron orbiting around the proton, we have
Therefore, the angular velocity is
b)
The period of revolution of the electron is given by
where
is the angular velocity
Substituting,
The period is the time the electron takes to make one complete orbit around the proton; therefore, the number of revolutions of the electrons in one second is:
rev/s
c)
The centripetal acceleration of an object in circular motion is
where
v is the linear speed
r is the radius of the circle
For the electron, we have
Therefore, the centripetal acceleration is
Learn more about circular motion:
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Answer:
Explanation:
This is quite tricky! You need to do 2 different equations to solve all the parts of this problem. First is finding the acceleration in one dimension, which has an equation of
F - f = ma
where F is the applied Friction,
f is the frictional force acting against F,
m is the mass of the object, and
a is the acceleration of the object (NOT the velocity!)
This is Newton's Second Law expanded on a bit. The sum of the forces working on an object is equal to the object's mass times its acceleration. We have F, but we need f which is found in the equation
f = μ which is the coefficient of kinetic friction times the weight of the object. Weight is found in the equation
w = mg where m is mass and g is the pull of gravity. Let's start there and work backwards:
w = 37(9.8) to 2 sig figs so
w = 360N. Now fill that in to find f:
f = (.17)(360) to 2 sig figs so
f = 61. Now for the final answer in the original equation way back up at the top:
85 - 61 = 37a and do the subtraction on the left side first:
24 = 37a and then we divide to 2 sig figs to get
a = .65 m/s/s
Since we are moving in a straight line (as opposed to on an angle) the displacement is found in
d = rt which simply says that the distance an object moves is equal to its rate times the time. Therefore,
d = 2.2(3.4) to 2 sig figs so
d = 7.5 m
Answer:
total number of electron in 1 litter is 3.34 × electron
Explanation:
given data
mass per mole = 18 g/mol
no of electron = 10
to find out
how many electron in 1 liter of water
solution
we know molecules per gram mole is 6.02 × molecules
no of moles is 1
so
total number of electron in water is = no of electron ×molecules per gram mole × no of moles
total number of electron in water is = 10 × 6.02 × × 1
total number of electron in water is = 6.02× electron
and
we know
mass = density × volume ..........1
here we know density of water is 1000 kg/m
and volume = 1 litter = 1 × m³
mass of 1 litter = 1000 × 1 ×
mass = 1000 g
so
total number of electron in 1 litter = mass of 1 litter ×
total number of electron in 1 litter = 1000 ×
total number of electron in 1 litter is 3.34 × electron