All categories

2 years ago

As light from a star spreads out and weakens, do gaps form between the photons?

Physics

2 answers:

Sati [7]2 years ago

8 0

Answer:

There are no gaps in space between the photons as they travel.

Yes, you can form the shadow of a fire

Explanation:

gtnhenbr [62]2 years ago

5 0

Yes you can form the shadow of a fire

You might be interested in

If mars has an orbital period of 1.84 years how far from the sun is it and how

EastWind [94]

141.6 million mi,and idk what u mean by how

6 0

3 years ago

Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant

Elena L [17]

Answer:

19 m/s

Explanation:

The complete question requires the final speed to be calculated.

Velocity is the rate and direction at which an object moves. Acceleration is the rate of change of velocity per unit time and can be calculated by the difference in velocity over a given time.

For this question, first the unknown acceleration must be calculated and used to determine the final velocity

Step 1: Calculate the acceleration

$a=\frac{v_{2}-v{1}}{t_{1}}$

$a=\frac{11-7}{8}$

$a=\frac{4}{8}$

$a=0.5 m/s^{2}$

Step 2: Calculate the velocity using the acceleration calculated above

$a=\frac{v_{3}-v{2}}{t_{2}}$

$0.5=\frac{v_{3}-11}{16}$

$v_{3}=19 m/s$

3 0

3 years ago

A particle moves at a constant speed of 34 m/s in a circular path of radius 6.3 m. From this information, what can be calculated

Yakvenalex [24]

Answer:

Centripetal acceleration

Explanation:

The centripetal acceleration is the motion inwards towards the center of a circular path.

Centripetal acceleration is given by; the square of the velocity, divided by the radius of the circular path.

That is;

ac = v²/r

Where; ac = acceleration, centripetal, m/s², v is the velocity, m/s and r is the radius, m

3 0

3 years ago

20% Part (a) Use an "E Field Sensor" and move it along either equipotential. What can you say about the E field along an equipot

Alex

Answer:

b. Constant magnitude, but varying direction, perpendicular to the equipotential.

Explanation:

As we know that the relation between electric field and electric potential is given as

$\Delta E = -\frac{dV}{dr}$

here if we say that potential is constant because electric field sensor is moving along equi-potential line.

Then we will say

V = constant

so we have

$\Delta E = 0$

so electric field will remain constant always in magnitude and always remains perpendicular to the surface

so we have

b. Constant magnitude, but varying direction, perpendicular to the equipotential.

6 0

3 years ago

A runner covers 40 m in 4.55 seconds ,what is their average velocity?

goldenfox [79]

Velocity = displacement/time

I hope i helped you <33

3 0

3 years ago