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Gekata [30.6K]
2 years ago
12

Emotional elevation only occurs in animal kin groups. please select the best answer from the choices provided t f

Physics
2 answers:
Lorico [155]2 years ago
8 0

Emotional elevation can occur in individuals or in groups, therefore, it is false that emotional elevation only occurs in animal kin groups.

<h3>What is emotional elevation?</h3>

Emotional elevation is the process whereby the moods of individuals are elevated due to their interactions with others or due to other factors.

Emotional elevation can occurs in individual animals or those on animal kin groups.

Therefore, it is false that emotional elevation only occurs in animal kin groups.

Learn more about emotional elevation at: brainly.com/question/8099018

#SPJ4

Pie2 years ago
3 0

Answer:

F

Explanation:

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From that, we say the whole universe is expanding, and that right there is
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Now:  If ... say tomorrow ... a competent Physicist discovers another way
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Now that our mind has been blown, come back down to Earth with me,
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6 0
3 years ago
Read 2 more answers
2. What kinds of statistics are used in sports? In a paragraph explain your answer with examples
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Explanation: BRAINLEST?

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2 years ago
A mechanism which uses mechanical energy to produce electrical energy is known as an) -
ser-zykov [4K]
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8 0
2 years ago
At what wavelength would a star radiate the greatest amount of energy if the star has a surface temperature of 60,000 K?
kompoz [17]

Answer:

\lambda=4.81\times 10^{-8}\ m

Explanation:

We have,

The surface temperature of the star is 60,000 K

It is required to find the wavelength of a star that radiated greatest amount of energy. Wein's displacement law gives the relation between wavelength and temperature such that :

\lambda T=2.89\times 10^{-3}

Here,

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\lambda=\dfrac{2.89\times 10^{-3}}{60000}\\\\\lambda=4.81\times 10^{-8}\ m

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7 0
2 years ago
A child has an ear canal that is 1.3 cm long. Assume the speed of sound is v = 344 m/s.
kap26 [50]

Answer:

The  frequencies are (f, f_1) =  (6615.4 \ Hz , 19846.2\ Hz)

Explanation:

From the question we are told that

  The  length of the ear canal is  l = 1.3 \ cm  =\frac{1.3}{100}  =  0.013 \ m

   The  speed of sound is assumed to be  v_s  =  344 \ m/s

Now  taking look at a typical  ear canal  we see that we assume it is  a  closed pipe

   Now the fundamental harmonics for the pipe(ear canal) is mathematically represented as

            f = \frac{v_s}{4 * l }

 substituting values  

          f = \frac{344}{4 * 0.013 }

         f = 6615.4 \ Hz

Also the the second harmonic for the pipe (ear canal) is mathematically represented as

        f_1 =  \frac{3v_s}{4 * l}

 substituting values  

       f_1 =  \frac{3 *  344}{4 * 0.013}

       f_1 =   19846.2 \ Hz

Given that sound would be loudest in the pipe at the frequency, it implies that the child  will have an increased audible sensitivity at this  frequencies

6 0
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