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Gekata [30.6K]
3 years ago
12

Emotional elevation only occurs in animal kin groups. please select the best answer from the choices provided t f

Physics
2 answers:
Lorico [155]3 years ago
8 0

Emotional elevation can occur in individuals or in groups, therefore, it is false that emotional elevation only occurs in animal kin groups.

<h3>What is emotional elevation?</h3>

Emotional elevation is the process whereby the moods of individuals are elevated due to their interactions with others or due to other factors.

Emotional elevation can occurs in individual animals or those on animal kin groups.

Therefore, it is false that emotional elevation only occurs in animal kin groups.

Learn more about emotional elevation at: brainly.com/question/8099018

#SPJ4

Pie3 years ago
3 0

Answer:

F

Explanation:

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A parallel circuit has three branches. Each branch has a resistance of 37.5 ohms. The total current is 7.5 amps. What is the cur
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Current in each branch will be 2.5 A

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While visiting the Albert Michelson exhibit at Clark University, you notice that a chandelier (which looks remarkably like a sim
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Answer:

a) 0,1613 Hz

b) 1,01342 rad/sec

c) 9.5422 m

d) 9.4314 m/sec^2

Explanation:

In the Albert Michelson exhibit at Clark University, we know the period of oscillation of the chandelier is T = 6.2 seconds

The chandelier will be modeled as a simple pendulum

a) Since the frequency is the reciprocal of the period, we have

f=\frac{1}{T}=\frac{1}{6.2sec}=0,1613 Hz

b) The angular frequency is computed as

w=2\pi f=2\pi (0,1613) = 1,01342\ rad/sec

c) The period of a simple pendulum is given by

T=2\pi \sqrt{\frac{L}{g}}

Where L is its length and g is the local acceleration of gravity (assumed 9.8 m/sec^2 for this part)

We want to know the length of the pendulum, so we isolate L

L=\frac{T^2g}{4\pi^2}

L=\frac{(6.2)^2(9.8))}{4\pi^2}=9.5422 m

d) While hanging out in J.J. Thompson’s House O’ Blues, the new period is 6.2+0.11=6.32 sec. Since the chandelier is the very same (same length), we can assume the gravity is slightly different. We use again the formula for T, but now we'll isolate g as follows

g=\frac{4\pi^2L}{T^2}=\frac{4\pi^2(9.5422m))}{(6.32sec)^2}

Which results  

g=9.4314\ m/sec^2

8 0
4 years ago
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