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2 years ago

Emotional elevation only occurs in animal kin groups. please select the best answer from the choices provided t f

2 answers:

8 0

Emotional elevation can occur in individuals or in groups, therefore, it is false that emotional elevation only occurs in animal kin groups.

<h3>What is emotional elevation?</h3>

Emotional elevation is the process whereby the moods of individuals are elevated due to their interactions with others or due to other factors.

Emotional elevation can occurs in individual animals or those on animal kin groups.

Therefore, it is false that emotional elevation only occurs in animal kin groups.

Learn more about emotional elevation at: brainly.com/question/8099018

#SPJ4

Pie2 years ago

3 0

Answer:

Explanation:

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Suppose you are in an elevator that is moving upward with a constant velocity. A scale inside the elevator shows your weight to

Ulleksa [173]

Answer:

a) Less than 600 N

b) 600 N

c) Less than 600 N

Explanation:

The value registered by the scale, measures the normal force on the object placed on the scale.

The person on the scale, is acted by two external forces, gravity (which we call weight, and always go downward) and the normal force, an upward force in this case.

The difference between both forces, according Newton’s 2nd law, must be equal to the product of the mass of the object, times the acceleration.

If the elevator moves upward to a constant speed, and then slows down, this means that there exists a net force on the person, producing a acceleration directed downwards on him.

If we take the direction of the acceleration (downward) to be positive, this means that the difference between gravity force and normal force must be positive.

As mg = 600 N (equal to normal force when no net force is present), the normal force in this case must be less than 600 N.

b) If the elevator is stopped, the effect is the same like it were moving at constant speed, so in this case the normal force remains the same: 600 N

c) Assuming that it starts from rest, if it accelerates going downward, and if we take as positive the downward direction, in order to satisfy Newton’s 2nd Law, normal force must be less than 600N so the difference between gravity and normal force remain positive.

4 0

3 years ago

Hat do the ancient civilizations of China, Egypt, and Greece have in common with regard to sports?

MAXImum [283]

The similarity among ancient civilizations of China, Egypt, and Greece with regard to sports is that they all organized athletic games that recurred annually.

I hope this helps! :)
~ erudite

5 0

2 years ago

Carly rode her bike for 300 meters in 30 seconds. One can calculate her

Nutka1998 [239]

Answer:

Explanation:

300 ÷ 30 = 10

Answer - 10

Hope this helps!!!

5 0

3 years ago

3. An object of mass 90 kg travels down a slide.

Zolol [24]

Gpe= 90* 9.81 * 15 = 13243.5 Joules

KE= 13243.5 =1/2 m v^2
v^2= 295.3
v= 17.2 m/s

6 0

3 years ago

Blood pressure is usually measured by wrapping a closed air-filled jacket equipped with a pressure gage around the upper arm of

Sever21 [200]

Answer:

a) High and low pressures are 15.999 kilopascals and 10.666 kilopascals, respectively.

b) High and low pressures are 2.320 pounds per square inch and 1.547 pounds persquare inch, respectively.

c) High and low pressures are 1.632 meters water column and 1.088 meters water column, respectively.

Explanation:

a) <em>High and low pressures in kilopascals</em>:

101.325 kPa equals 760 mm Hg, then, we can obtain the values by a single conversion:

$p_{high} = 120\,mm\,Hg\times \frac{101.325\,kPa}{760\,mm\,Hg}$

$p_{high} = 15.999\,kPa$

$p_{low} = 80\,mm\,Hg\times \frac{101.325\,kPa}{760\,mm\,Hg}$

$p_{low} = 10.666\,kPa$

High and low pressures are 15.999 kilopascals and 10.666 kilopascals, respectively.

b) <em>High and low pressures in pounds per square inch</em>:

14.696 psi equals 760 mm Hg, then, we can obtain the values by a single conversion:

$p_{high} = 120\,mm\,Hg\times \frac{14.696\,psi}{760\,mm\,Hg}$

$p_{high} = 2.320\,psi$

$p_{low} = 80\,mm\,Hg\times\frac{14.696\,psi}{760\,mm\,Hg}$

$p_{low} = 1.547\,psi$

High and low pressures are 2.320 pounds per square inch and 1.547 pounds persquare inch, respectively.

c) <em>High and low pressures in meter water column in meters water column</em>:

We can calculate the equivalent water column of a mercury column by the following relation:

$\frac{h_{w}}{h_{Hg}} = \frac{\rho_{Hg}}{\rho_{w}}$

$h_{w} = \frac{\rho_{Hg}}{\rho_{w}}\times h_{Hg}$ (Eq. 1)

Where:

$\rho_{w}$ , $\rho_{Hg}$ - Densities of water and mercury, measured in kilograms per cubic meter.

$h_{w}$ , $h_{Hg}$ - Heights of water and mercury columns, measured in meters.

If we know that $\rho_{w} = 1000\,\frac{kg}{m^{3}}$ , $\rho_{Hg} = 13600\,\frac{kg}{m^{3}}$ , $h_{Hg, high} = 0.120\,m$ and $h_{Hg, low} = 0.080\,m$ , then we get that: