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galben [10]
3 years ago
5

Zoe went on a fishing trip. On the first day she caught 9 catfish and 6 trout. On second caught 17 catfish and 13 trought. On wh

ich day of the fishing trip did zoe catch a lower ratio of catfish to trout?
Physics
1 answer:
denis23 [38]3 years ago
4 0

Answer:

<em>Zoe caught a lower ratio of catfish to trout on the second day of her fishing trip</em>

Explanation:

<u>Proportions and Ratios</u>

To compare two quantities we can perform them some 'test' operations like subtraction or division. If we subtract the first quantity from the second quantity, the difference can be positive if the second is greater, negative if the first is greater, or zero if they are equal.

A similar situation comes if we divide the last by the first. If the ratio (division) is greater than one, then the last quantity is greater than the first if it's less than one, the first is greater, and if it's exactly one, they are equal.

Zoe caught 9 catfish and 6 trout on her first day. It produces a ratio of 9/6=1.5 catfish to trout relation. The second day she caught 17 catfish and 13 trout, which gives us a ratio of 17/13=1.3 catfish to trout.

Based on the ratios we can say Zoe caught a lower ratio of catfish to trout on the second day of her fishing trip

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a uniform metre rule is pivoted at its centre and weights of 5 N and 12 N are hung at the 3 cm and 5 cm marks respectively. how
schepotkina [342]

In order to balance the stick on the pivot, the total "moments" must be equal on both sides.  A "moment" is (a weight) x (its distance from the center).

for the 5N weight: Moment = (5N) x (3 cm) = 15 N-cm

for the 12N weight: Moment = (12N) x (5 cm) = 60 N-cm

Sum of the moments trying to pull the stick down on that side = 75 N-cm

Whatever we hang on the other side has to provide a moment of 75 N-cm in the other direction.  We have a 25N weight. Where should we hang it ?  

(25N) x (distance from the pivot) = 75 N-cm

Distance from the pivot = (75 N-cm) / (25 N)

<em>Distance from the pivot =  3 cm </em>

8 0
3 years ago
During a neap tide, which phase could the moon be in? select all that apply
snow_lady [41]
Hello,

Here is your answer:

The proper answer to this question is option B "<span>third quarter".

Here is how:

Neap tides are caused when the moon is three thirds full which causes the current to up rise therefore making a neap tide.

Your answer is B.

If you need anymore help feel free to ask me!

Hope this helps!

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4 0
3 years ago
Read 2 more answers
2 Name the device in a car that we use to change the speed of the car
Crank

Answer:

Speedometer

Explanation:

Have a good day! :3

6 0
2 years ago
When the government sets a price for wheat that is above the equilibrium price, it is imposing a _____.
nalin [4]
<h3><u>Answer</u>;</h3>

Price floor

When the government sets a price for wheat that is above the equilibrium price, it is imposing a<u> price floor</u>.

<h3><u>Explanation</u>;</h3>
  • <u>Price floors prevent a price from falling below a certain level. When a price floor is set above the equilibrium price, quantity supplied will exceed quantity demanded, and excess supply. </u>
  • <u>Price control </u>occurs when the government laws regulate prices instead of letting market forces determine prices.
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3 years ago
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Be sure to answer all parts. By what factor does the fraction of collisions with energy equal to or greater than activation ener
qwelly [4]

Answer:

Factor = 8.77

Explanation:

Fraction of collision with energy greater than or equal to the activation energy  can be given by the formula:

f = \exp(\frac{-E_{a} }{RT} )

E_{a}  = Activation Energy\\E_{a}  = 100 kJ /mol\\E_{a}  = 10^{5} J /mol\\

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f_{1}  = \exp(\frac{-10^{5}  }{8.314 * 307} )\\f_{1} = \exp(\frac{-10^{5}  }{2552.398} )\\f_{1}  = \exp(-39.18)\\f_{1} = 964.59 * 10^{-20}

When Temperature =  52⁰C = 52 + 273 = 325 K

f_{2}  = \exp(\frac{-10^{5}  }{8.314 * 325} )\\f_{2}= \exp(\frac{-10^{5}  }{2702.05} )\\f_{2}= \exp(-37.009)\\f_{2} = 8456.6 * 10^{-20}

\frac{f_{2}}{f_{1}}= \frac{8456.6 * 10^{-20} }{964.59 * 10^{-20} }

Factor = 8.77

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