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galben [10]
3 years ago
5

Zoe went on a fishing trip. On the first day she caught 9 catfish and 6 trout. On second caught 17 catfish and 13 trought. On wh

ich day of the fishing trip did zoe catch a lower ratio of catfish to trout?
Physics
1 answer:
denis23 [38]3 years ago
4 0

Answer:

<em>Zoe caught a lower ratio of catfish to trout on the second day of her fishing trip</em>

Explanation:

<u>Proportions and Ratios</u>

To compare two quantities we can perform them some 'test' operations like subtraction or division. If we subtract the first quantity from the second quantity, the difference can be positive if the second is greater, negative if the first is greater, or zero if they are equal.

A similar situation comes if we divide the last by the first. If the ratio (division) is greater than one, then the last quantity is greater than the first if it's less than one, the first is greater, and if it's exactly one, they are equal.

Zoe caught 9 catfish and 6 trout on her first day. It produces a ratio of 9/6=1.5 catfish to trout relation. The second day she caught 17 catfish and 13 trout, which gives us a ratio of 17/13=1.3 catfish to trout.

Based on the ratios we can say Zoe caught a lower ratio of catfish to trout on the second day of her fishing trip

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iren [92.7K]

Answer:

Resistance = 400000 Ohms

Explanation:

Given the following data;

Voltage = 1200 V

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Voltage = current * resistance

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5 0
3 years ago
A mug rests on an inclined surface, as shown in (Figure 1) , θ=17∘.
Anna [14]
Refer to the figure shown below.

g =  9.8 m/s², the acceleration due to gravity.
W = mg, the weight of the mug.
θ = 17°, the angle of the ramp.

Let μ = the coefficient of static friction.

The force acting down the ramp is
F = W sin θ = W sin(17°) = 0.2924W N
The normal reaction is
N = W cosθ = W cos(17°) = 0.9563W N
The resistive force due to friction is
R = μN = 0.9563μW N

For static equilibrium,
μN = F
0.9563μW =0.2924W
μ = 0.3058

The frictional force is F = μN = 0.2924W
The minimum value of μ required to prevent the mug from sliding satisfies
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R > F
0.9563μW > 0.2924W
μ > 002924/.9563 = 0.306

Answer:
The frictional force is 0.2924mg, where m = the mass of the mug.
The minimum coefficient of static friction is 0.306

7 0
3 years ago
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An example of an atom that has no charge is one that has?
Pavlova-9 [17]

Answer: Equal number of protons and electrons. Example: an atom of oxygen atom  has 8 electrons and 8 protons and is neutral.

Explanation:

An atom that has no charge is a neutral atom. It contains electrons equal to protons. For example: A neutral atom of oxygen has 8 protons and 8 electrons.

An atom which has charge is said be ionized. It is either positively charged or negatively charged. It is positively charge when the number of electrons is less than the number of protons. For example: Na^+ contains 10 electrons and 11 protons.

And when the number of electrons is greater than the number of protons, the atom is negatively charged. For example, Cl^- has 17 protons and 18 electrons. It readily accepts an electron to complete its octet.

3 0
3 years ago
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A cart is pulled by a force of 250 N at an angle of 35° above the horizontal. The cart accelerates at 1.4 m/s2. The free-body di
Vikki [24]

Answer:

Mass of the cart = 146 kg

Explanation:

A cart is pulled by a force of 250 N at an angle of 35° above the horizontal.

The cart accelerates at 1.4 m/s² horizontally.

Horizontal force = Fcosθ = 250 cos35° = 204.79N

We have F = ma

Substituting

        204.79 = m x 1.4  

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Mass of the cart = 146 kg

3 0
3 years ago
A force of 4 kg weight acts on a body of mass 9.8 kg calculate the acceleration
White raven [17]

Answer:

here given is a weight

then force becomes mg

that is F=Mg

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Explanation:

3 0
3 years ago
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