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3 years ago

How does energy from the sun affect the motion of molecules in a gas compared to molecules in a liquid?

Physics

2 answers:

Nookie1986 [14]3 years ago

6 0

<h2>Answer:</h2>

Correct option is A.

a. Molecules in a gas move faster than in a liquid.

<h2>Explanation:</h2>

Energy from the sun affect the motion of molecules in a gas compared to molecules in a liquid such as that molecules in a gas move faster than in a liquid. So, first option is correct.

AnnZ [28]3 years ago

3 0

Molecules in a gas move faster than in a liquid.

hope it helps.

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What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your an

AveGali [126]

Complete Question

A Ferris wheel on a California pier is 27 m high and rotates once every 32 seconds in the counterclockwise direction. When the wheel starts turning, you are at the very top.

What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your answer as an angle between 0∘ and 360∘. Express your answer in degrees.

Answer:

$\phi=123.75$

Explanation:

From the question we are told that:

Height $h=27m$

Period $T=32sec$

Time $t=75sec$

Generally the equation for angular velocity is mathematically given by

$\omega=\frac{2 \pi}{T}$

$\omega=\frac{2 \pi}{32}$

$\omega=0.196rad/s$

Therefore

$\theta=\omega t$

$\theta=0.196rad/s*75sec$

$\theta=843.75 \textdegree$

Therefore

$\phi=\theta-2(360)$

$\phi=123.75$

6 0

3 years ago

You are packing for a trip to another star. During the journey, you will be traveling at 0.99c. You are trying to decide whether

Elenna [48]

Answer:

Do neither of these things ( c )

Explanation:

For length contraction : Is calculated considering the observer moving at a speed that is relative the object at rest applying this formula

L = (l) $\sqrt{1 -\frac{v^{2} }{c^{2} } }$

where l = Measured distance from object at rest, L = contracted measured in relation to the observer , v = speed of clock , c = speed of light

you will do neither of these things because before you can make such decisions who have to view the object in this case yourself from a different frame from where you are currently are, if not your length and width will not change hence you can't make such conclusions/decisions .

7 0

3 years ago

When a wave is acted upon by an external damping force what happens to the energy of the wave

Nimfa-mama [501]

Answer:

A-the energy of the wave decreases gradually

Explanation:

when a wave is acted upon by an external damping force the energy of the wave decreases gradually.

The energy degrades into the form of heat which is considered to be of less value and use. The reason is because it disperses and spreads more widely.

So therefore it end up as heat with a little sound but that is close to none because that too disperses into heat i.e. decreased form of energy.

4 0

4 years ago

A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. What is the vertical compon

elixir [45]

Answer:

Explanation:

Given the initial velocity U = 670m/s

Horizontal velocity Ux = Ucos theta

Vertical component of the cannon velocity Uy = Usin theta

Given

U = 670m/s

theta = 45°

horizontal component of the cannonball’s velocity = 670 cos 45

horizontal component of the cannonball’s velocity = 670(0.7071)

horizontal component of the cannonball’s velocity = 473.757m/s

Vertical component of the cannonball’s velocity = 670 sin 45

Vertical component of the cannonball’s velocity = 670 (0.7071)

Vertical component of the cannonball’s velocity = 473.757m/s

Hence pair of answer is 473.8 m/s; 473.8 m/s

6 0

3 years ago

Frost wedging occurs when water seeps into a crack in a rock, freezes, and causes the crack in the rock to widen.

Ilia_Sergeevich [38]

Answer:

the answer is true.

3 0

4 years ago