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lara [203]
2 years ago
15

Starting from rest, a 0.0367 kg steel ball sinks into a vat of corn syrup. The thick syrup exerts a viscous drag force that is p

roportional to the ball's velocity. → F drag = − C → v where C = 0.270 N ⋅ s/m is a constant related to the size and composition of the ball as well as the viscosity of the syrup. Find the rate at which gravitational energy is converted to thermal energy once the ball reaches terminal velocity.
Physics
1 answer:
Arisa [49]2 years ago
5 0

Answer:

0.48 W

Explanation:

Given that:

the mass of the steel ball = 0.0367 kg

C = 0.270 N

g (acceleration due to gravity) = 9.8

Now;

At Terminal Velocity Weight is balance by drag force

mg =Cv

Making v the subject of the formula:we have:

v = \frac  {mg}{C}

v = \frac  {0.0367*9.8}{0.270}

v = 1.332 m/s

Thus, the Rate at which gravitational energy is converted to thermal energy once the ball reaches terminal velocity is:

P=Fv

P = mgv

P = (0.0367*9.8)*1.332

P=0.48 W

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an electrically charged particle with mass m, velocity v, and charge q moves in a circle in magnetic field b. what is the formul
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3 years ago
1. When an object is at rest, not moving, and is crashed into by another
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2 years ago
A 3.00N rock is thrown vertically into the air from the ground. At h=15.0m, v=25m/s upward. Use the work-energy theorem to find
butalik [34]

Answer:

so initial speed of the rock is 30.32 m/s

correct answer is b. 30.3 m/s

Explanation:

given data

h = 15.0m

v = 25m/s

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solution

we use here work-energy theorem that is express as here

work = change in the kinetic energy    ..............................1

so it can be written as

work = force × distance     ...................2

and

KE is express as

K.E = 0.5 × m × v²  

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here

m is mass and vi and vf is initial and final velocity

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so put value in equation 3 we get

m  (-9.8) × 15 = 0.5 × m × (25)² - (vi)²

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so initial speed of the rock is 30.32 m/s

5 0
3 years ago
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