PLEASE HELP!!!!

Resistivity of metallic wire

bixtya [17]

Answer:

nature of material

hope this help you

6 0

3 years ago

While looking at a cliff, you observe that three visible layers of rocks are tilted about 30 degrees. There are four straight ho

xxTIMURxx [149]

Answer:

the principle of original horizontality and the principle of superposition

Explanation:

The principle of horizontality states that layers of sediment are originally deposited horizontally under the influence of gravity.

The principle of superposition states that the oldest layer layer is at the bottom and each layer above it is younger, with the youngest being at the top.

Unconformities help us find the age of different layers. An unconformity is a surface in which no new solid matter is deposited after a long geologic interval. Angular unconformity is a type of unconformity which different kinds of stratum were tilted or folded before deposition of younger layers of solid matter above the unconformity. Once the layers were folded and tilted, the older layers of the solid matter eroded, then the younger layers were deposited on the older layers. There angular unconformity is the contact between young and old layers of solid matter.

Therefore, these two principles therefore describe how the tilted layers are older than horizontal layers.

3 0

3 years ago

The noble gases neon (atomic mass 20.1797 u) and krypton (atomic mass 83.798 u) are accidentally mixed in a vessel that has a te

vagabundo [1.1K]

Answer:

(a) Kav Ne = Kav Kr = 7.29x10⁻²¹J

(b) v(rms) Ne= 659.6m/s and v(rms) Kr= 323.7m/s

Explanation:

(a) According to the kinetic theory of gases the average kinetic energy of the gases can be calculated by:

$K_{av} = \frac{3}{2}kT$ (1)

where $K_{av}$ : is the kinetic energy, k: Boltzmann constant = 1.38x10⁻²³J/K, and T: is the temperature

From equation (1), we can calculate the average kinetic energies for the krypton and the neon:

$K_{av} = \frac{3}{2} (1.38\cdot 10^{-23} \frac{J}{K})(352.2K) = 7.29\cdot 10^{-21}J$

(b) The rms speeds of the gases can be calculated by:

$K_{av} = \frac{1}{2}mv_{rms}^{2} \rightarrow v_{rms} = \sqrt \frac{2K_{av}}{m}$

where m: is the mass of the gases and $v_{rms}$ : is the root mean square speed of the gases

For the neon:

$v_{rms} = \sqrt \frac{2(7.29 \cdot 10^{-21}J)}{20.1797 \frac{g}{mol} \cdot \frac {1mol}{6.022\cdot 10^{23}molecules} \cdot \frac{1kg}{1000g}} = 659.6 \frac{m}{s}$

For the krypton:

$v_{rms} = \sqrt \frac{2(7.29 \cdot 10^{-21}J)}{83.798 \frac{g}{mol} \cdot \frac {1mol}{6.022\cdot 10^{23}molecules} \cdot \frac{1kg}{1000g}} = 323.7 \frac{m}{s}$

Have a nice day!

3 0

3 years ago

19. Determine the final state and its temperature when 150.0 kJ of heat are added to 50.0 g of water at 20 ºC. (Specific heat of

8090 [49]

The amount of energy to reach the boiling point is $50*80*4.184 J=16,736J$ . To pass the boiling point, $40.79*\frac{50}{18.02}kJ=113,180J$ are necessary (18.02 is the molar mass of water). This means that $150kJ-113.180kJ-16.736kJ=20,084J$ are left. This allows the steam to heat another $\frac{20,084}{50*1.99}=201.8^{\circ}C$ . Therefore, it ends as steam at temperature $100^{\circ}C+201.8^{\circ}C=301.8^{\circ}C$