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bazaltina [42]
3 years ago
12

Please help me with this question​

Physics
1 answer:
Oksanka [162]3 years ago
6 0

Car at rest:

velocity= 0m/s

Acceleration:

0.2m/s²

Since total time:

3 min = 180s

Formula of acceleration:

acceleration = [final velocity - initial velocity] ÷ [total time]

Velocity at end:

0.2m/s² = [final velocity - 0m/s] ÷ [180s]

0.2m/s² × 180s = [final velocity]

[final velocity] = 36m/s

Distance travelled:

Velocity = displacement(distance) ÷ time

36m/s = displacement(distance) ÷ 180s

displacement(distance) = 36m/s × 180s

displacement(distance) = 6480m

<em><u>Hey I'm sorry but i do not understand why the answer on your worksheet for distance travelled is 3240m... its </u></em><em><u>half</u></em><em><u> of what my answer is...</u></em>

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What are two pieces of information you must know about velocity on an object
levacccp [35]
Distance traveled(in a certain direction) and time
Velocity is all about direction traveled in comparison to speed which is just distance with out direction.


Hope this helps you
3 0
3 years ago
Agent Bond is standing on a bridge, 17 m above the road below, and his pursuers are getting too close for comfort. He spots a fl
faust18 [17]

Answer:

2 poles

Explanation:

We are told Agent Bond is standing on a bridge, 17 m above the road below.

Now, the bed of the truck is 1.5 m above the road.

It means the distance hewill need to fall = 17 - 1.5 = 15.5 m

acceleration due to gravity = 9.8 m/s²

Initial velocity = 0 m/s

Thus, to find the time, we will use the equation;

s = ut + ½at²

Plugging in the relevant values gives;

15.5 = 0 + ½9.8t²

Multiply through by 2 to give;

15.5 × 2 = 9.8t²

31 = 9.8t²

t² = 31/9.8

t = √(31/9.8)

t = 1.78 sec

We are told that he spots a flatbed truck approaching at 28 m/s and that the telephone poles are 22m apart.

Thus; The truck will pass the poles at a rate of; Velocity/distance between poles = 28/22 = 1.273 poles per second

Since, we got the time to be 1.78 seconds, then we can find the number of poles by multiplying it with the rate of poles per seconds.

Thus;

Number of poles = 1.78 second × 1.273 poles/ seconds = 2.27 poles

This is approximately 2 poles

6 0
3 years ago
HEL ME PLEASE I HAVE NO IDEA OF WHAT TO DO!!!!!!
Dahasolnce [82]

Answer:

b, the fastest the car has traveled out of those options is 4-5 seconds.

Explanation:

3 0
3 years ago
Read 2 more answers
How are scientific methods used to answer a question???
Oksanka [162]
You fallow the steps to figure out the complete answer of the question.
7 0
3 years ago
A 70-cm-diameter wheel accelerates uniformly from 160rpm to 280rpm in 4.0s. Determine (a) its angular acceleration, and (b) the
poizon [28]

Explanation:

Given that,

Diameter of the wheel, d = 70 cm = 0.7 m

Initial angular speed, \omega_i=160\ rpm=16.75\ rad/s

Final angular speed, \omega_f=280\ rpm=29.32\ rad/s

Time, t = 4 s

(a) Angular acceleration,

\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{29.32-16.75}{4}\\\\\alpha =3.14\ rad/s^2

(b) Tangential acceleration is :

a=r\alpha \\\\a=0.35\times 3.14\\\\a=1.085\ m/s^2  

Angular speed of the wheel after 2 seconds is :

\omega_f=\omega_i+\alpha t\\\\\omega_f=16.75+3.14\times 2\\\\\omega_f=23.03\ rad/s

Radial acceleration will be :

a=\omega_f^2r\\\\a=(23.03)^2\times 0.35\\\\a=185.6\ m/s^2

Hence, this is the required solution.

4 0
3 years ago
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