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Feliz [49]
3 years ago
5

A dog is facing a concave mirror. It is standing closer to the mirror than the focal point. From which location will the reflect

ed dog appear to be sitting?

Physics
2 answers:
Naddika [18.5K]3 years ago
8 0

Answer: Dog must stand outside the focal focal of the concave mirror.

Explanation:

In concave mirror, when ever an object is placed between the focal point and pole the image will be formed behind the mirror larger than the size of the actual object.

When an object is outside the focal point of the mirror then concave mirror will form a real and inverted image smaller than the original size of the object.

So in order to appear to be sitting the dog must stand outside the focal length of the concave mirror.

ohaa [14]3 years ago
7 0
The picture of the dog will frame behind the mirror. Just a concave mirror is equipped for delivering a genuine picture and this lone happens if the question is found a separation more noteworthy than a central length from the mirror's surface.
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Equal to change in momentum of larger mass.

Explanation:

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We know that

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Change in momentum for small mass=F\Delta t

Because Force and length of time are same for both masses .

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Centripetal force is a centering force related to acceleration. The centripetal force when driving prevents which of the followi
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Answer:

P=3.42×10^-6 J/s

Explanation:

From the kinematics of motion with constant acceleration we know that :  

vf^2=vi^2+2*a(xf-xi)

Where :

• vf , vi, are the the final and the initial velocity of the electron  

• a is the acceleration of the electron  

• xf , xi are the final and the initial position of the electron .

Strategy for solving the problem : at first from the given information we calculate the acceleration of the electron.  

Givens: vf = 8.4 x 10^7 m/s , vi, = 0 m/s , xf = 0.025 m and xi = 0 m  

vf^2 =vi^2+2*a(xf-xi)

vf^2-vi^2=2*a(xf-xi)

2*a(xf-xi)= vf^2-vi^2

          a = (vf^2-vi^2)/2(xf-xi)

Pluging known information to get :

a = (vf^2-vi^2)/2(xf-xi)

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vf^2 =5.312× 10^7

From the following Eq. we can calculate the time elapsed in this motion .  

xf =xi+vi*t+1/2*a*t

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  t=√2(xf-xi)/a

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now we can use the power P Eq.  

 P=W/Δt => ΔK/Δt  

Where: the work done W change the kinetic energy K of the electron ,

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P=1/2*m*vf^2-1/2*m*vi^2/Δt

P=3.42×10^-6 J/s

6 0
2 years ago
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