To loosen the lid on a jar of jam 8.9 cm in diameter a torque of 7.5 n·m must be applied to the circumference of the lid. if a j
ar wrench whose handle extends 13 cm from the center of the jar is attached to the lid, what is the minimum force required to open the jar?
1 answer:
Refer to the diagram shown below.
F = the minimum force required for opening the lid
r = 8.9/2 = 4.45 cm = 0.0445 m
P = the applied force, aplied at a distance of 13 cm = 0.13 m.
Because the required torque is 7.5 N-m, therefore
(0.13 m)*(P N) = 7.5 N-m
P = 57.6923 N
The equation for the lever requires that
0.13P = 0.0445F = 7.5
Therefore
F = 7.5/.0445 = 168.54 N
Answer: 168.5 N
F = the minimum force required for opening the lid
r = 8.9/2 = 4.45 cm = 0.0445 m
P = the applied force, aplied at a distance of 13 cm = 0.13 m.
Because the required torque is 7.5 N-m, therefore
(0.13 m)*(P N) = 7.5 N-m
P = 57.6923 N
The equation for the lever requires that
0.13P = 0.0445F = 7.5
Therefore
F = 7.5/.0445 = 168.54 N
Answer: 168.5 N
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