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Aleks [24]
3 years ago
14

Now, perform the experiment. Using the straw, blow air onto the sand in pan 3. Then use the hair dryer to blow air on the sand i

n pan 4. Write down your observations about the sand in each pan.
Weathering, Erosion
Pleasssseee help mee
Physics
2 answers:
Fiesta28 [93]3 years ago
8 0
How can i help when we don’t see the experiment?
Zina [86]3 years ago
4 0
I do not know the exact question. But I can explain what weathering and erosion is to possibly help you.
Weathering- The process of wearing or being worn by long exposure to the atmosphere. (Usually rain and wind).
Erosion-The process of eroding or being eroded by wind, water, or other natural agents. (Such as acid rain over time slowly cutting into a rock and breaking it down into minerals).
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Multiple choice please help :)
oee [108]

Answer:

oh i would have to do alot to answer that

7 0
3 years ago
If he were able to maintain this constant rate of acceleration, what would have been his speed as he finished the race?
Law Incorporation [45]

a) 4.8 m/s² his average acceleration during the first 2.5 s

b) 15 m distance he cover during the first 2.5 seconds.

c) 31 m/s his speed as he finished the race.

<h3>(a) How to calculate the Average Acceleration ?</h3>

Average acceleration is calculated by using Newtons first law of motion

v = u + at

where

u is initial velocity

v is final velocity

a is constant acceleration

t is time

Given u = 0m/s , v = 12 m/s and t = 2.5 sec

Therefore average acceleration is given by

a=\frac{v}{t}

a=\frac{12}{2.5}

a = 4.8 m/sec²

b) Here we will use newtons second law of motion

s=ut+\frac{1}{2}at^{2}

On substituting value we get

s = 15m

c) Here we will use newtons third law of motion

v² = u² + 2as

Here u = 0 , a = 4.8 m/s² and s = 100 m

Therefore

v² = 960

v = 31 m/s

Disclaimer: the question was given incomplete in the portal. Here is the complete question.

Question: Usain Bolt's 100m sprint Runner set the world record for the100 meter sprint during the 2009World Championships in Berlin with a time of 9.58 s, reaching a top speed of 12 m/s in about 2.5 s.

a. What was his average acceleration during the first 2.5 s?

b. What distance did he cover during the first 2.5 seconds, assuming his acceleration was constant?

c. If he were able to maintain this constant rate of acceleration, what would have been his speed as he finished the race?

Learn more about Newtons law of motion here:

brainly.com/question/12525794

#SPJ4

5 0
2 years ago
A teacher did an experiment to show the movement of particles in solids, liquids, and gases. The experimental set-up is shown be
ELEN [110]

Answer: Option (B) is the correct answer.

Explanation:

In a solid, molecules are held together by strong intermolecular forces of attraction. As a result, they are unable to move from their initial place but they can vibrate at their mean position.

Hence, in solid substances the molecules have low kinetic energy.

Whereas in liquids, the molecules are held by less strong intermolecular forces of attraction as compared to solids. Due to which they are able to slide past each other. Hence, they have medium kinetic energy.

In gases, the molecules are held by weak Vander waal forces. Hence, they have high kinetic energy due to which they move rapidly from one place to another leading to more number of collisions.

Hence, gases are able to expand more rapidly as compared to liquids.

Thus, we can conclude that out of the given options solid = low; liquid = medium; gas = high, combination of the state of matter and the corresponding dryer speed is correct.

8 0
4 years ago
How do you start the game of floor hockey
babunello [35]

Answer:

3

Explanation:

because it did=

4 0
3 years ago
A cylinder has 500 cm3 of water. After a mass of 100 grams of sand is poured into the cylinder and all air bubbles are removed b
Nina [5.8K]

Answer: SG = 2.67

Specific gravity of the sand is 2.67

Explanation:

Specific gravity = density of material/density of water

Given;

Mass of sand m = 100g

Volume of sand = volume of water displaced

Vs = 537.5cm^3 - 500 cm^3

Vs = 37.5cm^3

Density of sand = m/Vs = 100g/37.5 cm^3

Ds = 2.67g/cm^3

Density of water Dw = 1.00 g/cm^3

Therefore, the specific gravity of sand is

SG = Ds/Dw

SG = (2.67g/cm^3)/(1.00g/cm^3)

SG = 2.67

Specific gravity of the sand is 2.67

3 0
3 years ago
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