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mars1129 [50]
3 years ago
15

A molecule of pentane is made of 5 carbon atoms and 12 hydrogen atoms. a collection of pentane molecules has 3.01 x 1024 carbon

atoms. how many hydrogen atoms are in the collection? 3.01 × 1024 × (12/5) hydrogen atoms (3.01 × 1024 / 5) hydrogen atoms 3.01 × 1024 × (5/12) hydrogen atoms 3.01 × 1024 × 12 hydrogen atoms description
Chemistry
2 answers:
zimovet [89]3 years ago
8 0

3.01 x 10^24 x (12/5) hydrogen atoms

Novay_Z [31]3 years ago
5 0

3.01 Ă— 10^24 Ă— (12/5) hydrogen atoms  
Looking at the formula for the molecule, the ratio of carbon to hydrogen atoms is 5:12, so if we divide the number of carbon atoms by 5 and then multiply by 12, we can find the number of hydrogen atoms. Let's look at the available options and see what makes sense.  
3.01 Ă— 10^24 Ă— (12/5) hydrogen atoms 
* This is exactly correct.  
(3.01 Ă— 10^24 / 5) hydrogen atoms 
* Nope. This will tell you how many pentane MOLECULES you have, but not the number of hydrogen atoms.  
3.01 Ă— 10^24 Ă— (5/12) hydrogen atoms 
* Close, but the ratio (5/12) will tell you the number of carbon atoms you have if you give it the number of hydrogen atoms. So this choice is wrong.  
3.01 Ă— 10^24 Ă— 12 hydrogen atoms description 
* This would tell you the number of hydrogen atoms you have if you know the number of pentane molecules you have. So this choice is also wrong.
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= 81.24 g

Explanation:

The Balanced chemical equation for this reaction is :

Cu(s) + S\rightarrow CuS

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Moles = \frac{given\ mass}{Molar\ mass}

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Moles = \frac{given\ mass}{Molar\ mass}

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Limiting Reagent :<em> The reagent which is present in less amount and consumed in a reactio</em>n

<u><em>First find the limiting reagent :</em></u>

Cu + S\rightarrow CuS

1 mol of Cu require = 1 mol of S

0.8497 mol of Cu should require  = 1 x 0.8497 mol

= 0.8497 mol of S

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S Required  = 0.8497 mol

S is present in excess and <u>Cu is limiting reagent</u>

<u>All Cu is consumed in the reaction</u>

Amount Cu will decide the amount of CuS formed

Cu + S\rightarrow CuS

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0.8497 mol of Cu =  1 x 0.8497 mole of Copper sulfide

= 0.8497

Molar mass of CuS = 95.611 g/mol

Moles = \frac{given\ mass}{Molar\ mass}

0.8497 = \frac{given\ mass}{95.611}

Mass of CuS = 0.8497 x 95.611

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