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mars1129 [50]
3 years ago
15

A molecule of pentane is made of 5 carbon atoms and 12 hydrogen atoms. a collection of pentane molecules has 3.01 x 1024 carbon

atoms. how many hydrogen atoms are in the collection? 3.01 × 1024 × (12/5) hydrogen atoms (3.01 × 1024 / 5) hydrogen atoms 3.01 × 1024 × (5/12) hydrogen atoms 3.01 × 1024 × 12 hydrogen atoms description
Chemistry
2 answers:
zimovet [89]3 years ago
8 0

3.01 x 10^24 x (12/5) hydrogen atoms

Novay_Z [31]3 years ago
5 0

3.01 Ă— 10^24 Ă— (12/5) hydrogen atoms  
Looking at the formula for the molecule, the ratio of carbon to hydrogen atoms is 5:12, so if we divide the number of carbon atoms by 5 and then multiply by 12, we can find the number of hydrogen atoms. Let's look at the available options and see what makes sense.  
3.01 Ă— 10^24 Ă— (12/5) hydrogen atoms 
* This is exactly correct.  
(3.01 Ă— 10^24 / 5) hydrogen atoms 
* Nope. This will tell you how many pentane MOLECULES you have, but not the number of hydrogen atoms.  
3.01 Ă— 10^24 Ă— (5/12) hydrogen atoms 
* Close, but the ratio (5/12) will tell you the number of carbon atoms you have if you give it the number of hydrogen atoms. So this choice is wrong.  
3.01 Ă— 10^24 Ă— 12 hydrogen atoms description 
* This would tell you the number of hydrogen atoms you have if you know the number of pentane molecules you have. So this choice is also wrong.
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How many moles are in 3.00x 10^22 atoms of He?
sp2606 [1]

Answer:

<h2>0.05 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.0 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.049833...

We have the final answer as

<h3>0.05 moles</h3>

Hope this helps you

3 0
2 years ago
Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine. CCl4(g) + (1/2)O
madam [21]

The question is incomplete, here is the complete question:

Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine.

CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c=4.4\times 10^9 at 1,000 K

Calculate Kc for the reaction 2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)

<u>Answer:</u> The value of K_c' for the final reaction is 1.936\times 10^{19}

<u>Explanation:</u>

The given chemical equations follows:

CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c

We need to calculate the equilibrium constant for the equation, which is:

2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)

As, the final reaction is the twice of the initial equation. So, the equilibrium constant for the final reaction will be the square of the initial equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c'=(K_c)^2

We are given:

K_c=4.4\times 10^9

Putting values in above equation, we get:

K_c'=(4.4\times 10^9)^2=1.936\times 10^{19}

Hence, the value of K_c' for the final reaction is 1.936\times 10^{19}

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<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2>

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<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>

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