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3 years ago

What do leaves produce

Chemistry

2 answers:

murzikaleks [220]3 years ago

7 0

Plants Produce Oxygen and we produce carbon dioxide to give the plants therefore they give oxygen back

larisa86 [58]3 years ago

6 0

They produce air/oxygen.

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Unit 2 Test

Dafna11 [192]

Answer:

the answer to this question is producer

3 0

3 years ago

A solution is prepared by mixing 93.0 mL of 5.00 M HCl and 37.0 mL of 8.00 M HNO3. Water is then added until the final volume is

Charra [1.4K]

Answer:

$[H^{+}] = 0.761 \frac{mol}{L}$

$[OH^{-}]=1.33X10^{-14}\frac{mol}{L}$

$pH = 0.119$

Explanation:

HCl and HNO₃ both dissociate completely in water. A simple method is to determine the number of moles of proton from both these acids and dividing it by the total volume of solution.

$n_{H^{+} } from HCl = [HCl](\frac{mol}{L}). V_{HCl}(L) \\ n_{H^{+} } from HNO_{3} = [HNO_{3}](\frac{mol}{L}). V_{HNO_{3}}(L)$

Here, n is the number of moles and V is the volume. From the given data moles can be calculated as follows

$n_{H^{+} } from HCl = (5.00)(0.093)$

$n_{H^{+} } from HCl = 0.465 mol$

$n_{H^{+} } from HNO_{3} = (8.00)(0.037)$

$n_{H^{+} } from HNO_{3} = 0.296 mol$

$n_{H^{+}(total) } = 0.296 + 0.465$

$n_{H^{+}(total) } = 0.761 mol$

For molar concentration of hydrogen ions:

$[H^{+}] = \frac{n_{H^{+}}(mol)}{V(L)}$

$[H^{+}] = \frac{0.761}{1.00}$

$[H^{+}] = 0.761 \frac{mol}{L}$

From dissociation of water (Kw = 1.01 X 10⁻¹⁴ at 25°C) [OH⁻] can be determined as follows

$K_{w} = [H^{+} ][OH^{-} ]$

$[OH^{-}]=\frac{Kw}{[H^{+}] }$

$[OH^{-}]=\frac{1.01X10-^{-14}}{0.761 }$

$[OH^{-}]=1.33X10^{-14}\frac{mol}{L}$

The pH of the solution can be measured by the following formula:

$pH = -log[H^{+} ]$

$pH = -log(0.761)$

$pH = 0.119$

5 0

3 years ago

Consider the following substances: hydrogen gas (H2), carbon dioxide (CO2), Sulfur (S8). neon (Ne) and propane (C3H8). Which sub

alexgriva [62]

hydrogen gas (H2), COMPOUND

carbon dioxide (CO2), COMPOUND

Sulfur (S8). ELEMENT

neon (Ne) ELEMENT

and propane (C3H8).COMPOUND

Explanation:

7 0

3 years ago

What is the mass of bromine in 11.2g of MgBr2?

True [87]

Answer:

9.72 grams of Br

Explanation:

This is the salt: MgBr₂ (Magnesium bromide)

1 mol of MgBr₂ has 1 mol of Mg and 2 mol of Br

Molar mass MgBr₂ → 184.11 g/m

So the rule of three will be:

184.11 g of salt have 2 moles of Br

11.2 g of salt have (11.2 . 2)/184.11 = 0.122 moles of Br.

Molar mass Br = 79.9 g/m

Mol . molar mass = mass → 0.122 m . 79.9 g/m = 9.72 g

8 0

3 years ago

Please awnser these questions on the picture 50 points

harkovskaia [24]

1 － valence electrons
2 － electrons
3 － two electrons
4 － eight electrons
5 － eighteen electrons
6 － nucleus
7 － protons
8 － neutrons
9 － shell or energy level
10－ atomic number
11 － element symbol
12 － atomic name
13 － atomic mass

7 0

3 years ago

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