What will the core contain

How many significant figures does 0.0006510 of have?

arsen [322]

It has 4 significant figures. If you see the Zero after the one decimal point you don’t count that and instead just started at 6

7 0

3 years ago

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When chemicals react with each other which factors decide that a successful reaction has taken place ?

Elodia [21]

The factors that affect the rate of a reaction are:

nature of the reactant - when reactants with different chemical composition are exposed to same conditions they would react differently. For instance, when an acid or base is added on litmus paper, blue litmus paper turns red in presence of acid while red litmus paper turns blue when base is added.
surface area- a compound with small pieces spread over a large area will react faster than a big lump of a compound occupying a small area.
temperature of reaction- reactants would react faster at high temperatures. this is because they have higher kinetic energy to collide with each other. Hence a plate of food on the table spoils faster than a plate of food in the fridge.
concentration- an increase in concentration leads to more molecules available to collide and form products. An example, when you add more of indicator in a solution, the color becomes more clear since more particles react to give more color.
presence of a catalyst- a catalyst lowers the activation energy, which means less energy is required to shift reaction in forward direction. In the presence of iron (Fe) a catalyst, nitrogen N₂ and hydrogen H₂ react to produce NH₃

3 0

3 years ago

How many different 3d states does the hydrogen atom have?

Taya2010 [7]

An electron in a hydrogen atom would have 10 states for a 3d orbital, like any other element.

n = 3, l = 2, in one of ml = 2, 1, 0, -1, -2 each with ms = -½ or +½ or a total of 10 possible states.

None of these are a ground state of an electron in the hydrogen atom.

Enjoy :)

6 0

3 years ago

A solution of Cuso, is labelled 1.743 M. How much Cuso, in grams, must be used to make

zepelin [54]

Answer:

Option A. 416.1 g.

Explanation:

Data obtained from the question include the following:

Molarity = 1.743 M

Volume = 1.4957 L

Mass of CuSO4 =..?

Next, we shall determine mole of CuSO4 present in the solution.

This is illustrated below:

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the mole CuSO4 present in the solution as follow:

Molarity = 1.743 M

Volume = 1.4957 L

Mole of CuSO4 =..?

Molarity = mole /Volume

1.743 = mole of CuSO4 /1.4957

Cross multiply

Mole of CuSO4 = 1.743 x 1.4957

Mole of CuSO4 = 2.607 moles

Finally, we shall convert 2.607 moles of CuSO4 to grams.

This can be obtained as follow:

Molar mass of CuSO4 = 63.55 + 32.06 + (16x4) = 159.61 g/m

Mole of CuSO4 = 2.607 moles

Mass of CuSO4 =..?

Mole = mass /molar mass

2.607 = mass of CuSO4 /159.61

Cross multiply

Mass of CuSO4 = 2.607 x 159.61

Mass of CuSO4 = 416.1 g

Therefore, 416.1 g of CuSO4 is needed to prepare the solution.

7 0

3 years ago

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Mr. Whiteman has two stock solutions of sulfuric acid (H2SO4) in the supply closet: 12.1 M and 6.0 M. If he wants to make 10.0 m

ss7ja [257]

Answer:

12.1-M requires less volume of stock solution.

Explanation:

Hello there!

In this case, according to the foundations of dilution processes, it turns out convenient to remember that the moles of the solute before and after the dilution remains the same; for that reason we use the following equation:

$M_1V_1=M_2V_2$

Relating the initial and final molarities and volumes. Now, it is seen that V2 is 10.0 mL and M2 is 1.0 M, which means that if we solve for V1 for 12.1 M and 6.0 M, we obtain the following volumes:

$V_1=\frac{M_2V_2}{M_1} \\\\V_1^{12.1M}=\frac{1.0M*10.0 mL}{12.1M}=0.826mL\\\\V_1^{6.0M}=\frac{1.0M*10.0 mL}{6.0M}=1.67mL$

Therefore, since the 12.1-M solution requires less volume of stock solution, it makes sense to use this one as the initial solution.

Best regards!

5 0

3 years ago