Answer:
Muscular contractions that moves food along the digestive tract.
<u>Answer:</u> When bleach is mixed with water, it produces hypochlorous acid.
<u>Explanation:</u>
The chemical name for bleach is sodium hypochlorite. When this compound is reacted with water, it produces hypochlorous acid and sodium hydroxide.
The chemical equation for the reaction of sodium hypochlorite and water follows:

By Stoichiometry of the reaction:
1 mole of sodium hypochlorite reacts with 1 mole of water to produce 1 mole of hypochlorous acid and 1 mole of sodium hydroxide.
Hence, when bleach is mixed with water, it produces hypochlorous acid.
Answer:
D. Ionic compound
Explanation:
Just based on my opinion
Correct me if I'm wrong tnx:<
Answer:
The mass percent of Al(OH)₃ is 15.3%
Explanation:
The reaction is:
Al(OH)₃ + 3HCl = AlCl₃ + 3H₂O
The excess acid is neutralized with a solution of sodium hidroxide, in the reaction:
NaOH + HCl = NaCl + H₂O
The total moles of HCl is:

From the second titration, the moles of excess of HCl is:

The difference between the total and excess of HCl, it can be know the moles that reacts with the aluminum hydroxide, is:

The ratio between HCl and Al(OH)₃ is 3:1. The MW for aluminum hydroxide is 78 g/mol, thus:

The percentage of Al(OH)₃ is:
%
Whewww!! What class is this for