<u>Answer:</u> The concentration of ions is 0.10 M and that of
ions is 0.30 M
<u>Explanation:</u>
We are given:
Concentration of = 0.10 M
The chemical equation for the ionization of aluminium bromide follows:
1 mole of aluminium bromide produces 1 mole of aluminium ions and 3 moles of bromide ions
So, concentration of aluminium ions = 0.10 M
Concentration of bromide ions =
Hence, the concentration of ions is 0.10 M and that of
ions is 0.30 M
Answer:
2-bromo-4 methylheane
Explanation:
Numbering from right to left, the bromine atom falls on the second (2) carbon, while the methyl branch on the 4th.
The systematic naming (IUPAC) of haloalkanes follows the alphabetical rule in naming the substituents, be it alkyl groups or halogens.
I hope the explanation would suffice.
<u>Answer:</u>
<u>For A:</u> The total pressure in the flask at equilibrium is 1.19 atm
<u>For B:</u> The value of for the given equation is 2.016
<u>Explanation:</u>
We are given:
Initial partial pressure of A = 0.77 atm
Equilibrium partial pressure of A = 0.35 atm
For the given chemical equation:
<u>Initial:</u> 0.77
<u>At eqllm:</u> 0.77-x 2x
Evaluating the value of 'x'
Equilibrium partial pressure of B = 2x = (2 × 0.42) = 0.84 atm
Total pressure in the flask at equilibrium =
Hence, the total pressure in the flask at equilibrium is 1.19 atm
The expression of for given equation follows:
Putting values in above expression, we get:
Hence, the value of for the given equation is 2.016