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Angelina_Jolie [31]
3 years ago
6

How much work does a gas do when it expands against a constant pressure of 0.600 atm from a volume of 50.00 mL to a volume of 44

0.00 mL?
Chemistry
1 answer:
miskamm [114]3 years ago
3 0

Answer:

23.71J is the work that the gas do.

Explanation:

The work that a gas do under isobaric conditions follows the formula:

W = P*ΔV

<em>Where W is work in atmL, P is the pressure and ΔV is final volume -Initial volume In Liters</em>

Replacing with the values of the problem:

W = P*ΔV

W = 0.600atm*(0.44000L - 0.0500L)

W = 0.234atmL

In Joules (1atmL = 101.325J):

0.234atmL × (101.325J / 1 atmL) =

<h3>23.71J is the work that the gas do.</h3>

<em />

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Consider the reaction: A &lt;=&gt; B. Under standard conditions at equiliubrium, the concentrations of the compounds are [A] = 1
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Answer:

Keq'>1\\\Delta G'

Explanation:

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In this case, for the given reaction, the equilibrium constant turns out:

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Methane at 10 mpa and 300 k is heated at constant pressure until its volume has increased by 80 percent. determine the final tem
katovenus [111]
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PV = nRT, where

P is the pressure
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When the process goes under constant pressure (and assuming same number of moles),

P/nR = T/V = constant, therefore,

T₁/V₁=T₂/V₂

If V₂ = V₁(1+0.8) = 1.8V₁, then,

T₂/T₁ = 1.8V₁/V₁

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If you do not assume ideal gas, you use the compressibility factor, z. The gas equation would now become

PV =znRT

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7 0
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Suppose that 2.14 grams of H2SO4 is mixed with enough water to make 225 mL of solution. Determine the Molarity (M) of the soluti
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Answer:

0.0970 M

Explanation:

Remember this equation:

mol/M x V

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0.0218/0.225

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6 0
3 years ago
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