Answer:
The 12L helium tank pressurized to 160 atm will fill <em>636 </em>3-liter balloons
Explanation:
It is possible to answer this question using Boyle's law:
Where P₁ is the pressure of the tank (160atm), V₁ is the volume of the tank (12L), P₂ is the pressure of the balloons (1atm, atmospheric pressure) And V₂ is the volume this gas will occupy at 1 atm, thus:
160atm×12L = 1atm×V₂
V₂ = 1920L
As the tank will never be empty, the volume of the gas able to fill balloons is the total volume minus 12L, thus the volume of helium able to fill balloons is:
1920L - 12L = 1908L
1908L will fill:
1908L×
= <em>636 balloons</em>
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I hope it helps!
Answer:
The oxidation state of N in the KNO3 is +5
Explanation:
Oxidation rules:
1. Oxygen is -2, unless in peroxides.
2. Group 1 metals = +1
3. Group 2 metals = +2
4. If the molecule is neutral, all of the oxidation numbers have to add up to zero.
5. If the molecule is charged, all of the oxidation numbers have to add up to the charge of the molecule.
So, the given formula represents the salt compound formula unit of potassium nitrate: KNO3
The formula unit is uncharged.
From our rules, we know that,
O = -2
And we can find K on the periodic table, in the first group, thus giving it a +1 charge. Now let's put it all together.
K = +1
N = x
O = -2
Let's take into account the number of atoms of each element we have and make an equation since we know everything has to add up to zero since the molecules are neutral.
+1 +x+3 (-2) = 0 (notice we multiplied 3 by -2 because in the formula we have 3 atoms of oxygen with -2 charge each)
x - 5 = 0
x = 5
Therefore, the oxidation number of N in KNO3 is +5.
Its has 24 protons, 24 electrons, and 28 nuetrons
Answer:
first one-liquids dont have a fixed shape and solids do
Answer :
Compound : It is a mixture of elements which are chemically bonded together in a fixed proportions.
(a) Citric acid, 
In this compound, there are three types of elements present carbon, hydrogen and oxygen. There are 6 atoms of carbon element, 8 atoms of hydrogen element and 7 atoms of oxygen element.
(b) Glycine, 
In this compound, there are four types of elements present carbon, hydrogen, nitrogen and oxygen. There are 2 atoms of carbon element, 5 atoms of hydrogen element, 1 atom of nitrogen element and 2 atoms of oxygen element.
(c) Chloroform, 
In this compound, there are three types of elements present carbon, hydrogen and chlorine. There are 1 atom of carbon element, 1 atom of hydrogen element and 3 atoms of chlorine element.
(d) Sulfur hexafluoride, 
In this compound, there are two types of elements present sulfur and fluorine. There are 1 atom of sulfur element and 6 atoms of fluorine element.
